I don’t know how to answer :’(
Answer:
The dial bore gauge measures the inside of round holes, such as the bearing journals. This one tool can measure 2″ up to 6″ diameter holes. Both tools are needed in order to check the interior and exterior dimensions of the crankshaft, rods and engine block journals, as well as the thickness of the bearings themselves.
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Answer:
connecting two independent clauses
Answer:
(N-1) × (L/2R) = (N-1)/2
Explanation:
let L is length of packet
R is rate
N is number of packets
then
first packet arrived with 0 delay
Second packet arrived at = L/R
Third packet arrived at = 2L/R
Nth packet arrived at = (n-1)L/R
Total queuing delay = L/R + 2L/R + ... + (n - 1)L/R = L(n - 1)/2R
Now
L / R = (1000) / (10^6 ) s = 1 ms
L/2R = 0.5 ms
average queuing delay for N packets = (N-1) * (L/2R) = (N-1)/2
the average queuing delay of a packet = 0 ( put N=1)
Answer:
$916
Explanation:
To solve this, we use the formula
FV = P/i * [(1+i)^n - 1], where
FV = future value of the all the money invested, $5 million
n = time span, = 500 months
P = payment per month
I = interest rate, 9% by 12 months, = 0.0075
Considering that we have been given all in our question, then we substitute directly and solve. So we have,
5000000 = P/0.0075 * [(1+0.0075)^500 -1]
5000000 * 0.0075 = P * [1.0075^500 - 1]
37500 = P * [41.93 - 1]
37500 = P * 40.93
P = 37500/40.93
P = $916.20
Therefore, the engineer needs to save $916 in a month which is the accrued
