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valkas [14]
4 years ago
10

Who plays a role in the financial activities of a company?

Engineering
1 answer:
KatRina [158]4 years ago
3 0

Hey,

Who plays a role in the financial activities of a company?

<em>O D. Everyone at the company, including managers and employees</em>

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A Si sample contains 1016 cm-3 In acceptor atoms and a certain number of shallow donors, the In acceptor level is 0.16 eV above
creativ13 [48]

Answer:

6.5 × 10¹⁵/ cm³

Explanation:

Thinking process:

The relation N_{o} = N_{i} * \frac{E_{f}-E_{i}  }{KT}

With the expression Ef - Ei = 0.36 × 1.6 × 10⁻¹⁹

and ni = 1.5 × 10¹⁰

Temperature, T = 300 K

K = 1.38 × 10⁻²³

This generates N₀ = 1.654 × 10¹⁶ per cube

Now, there are 10¹⁶ per cubic centimeter

Hence, N_{d}  = 1.65*10^{16}  - 10^{16} \\           = 6.5 * 10^{15} per cm cube

5 0
3 years ago
Read 2 more answers
To protect their employees from caught-in and -between hazards, what must employers do?
marusya05 [52]

Answer:

Employers must comply with OSHA's regulations to safeguard workers from caught-in or -between dangers, which include, but are not limited to, the following:

• Protect power tools and other equipment with moving parts with guards.

• Support, secure, or otherwise make safe any equipment that has pieces that workers could become entangled in.

· Take precautions to avoid workers being crushed by tipped-over heavy machinery.

• Take precautions to avoid pinning workers between equipment and a solid object.

• Provide workers with protection when trenching and excavating.

• Provide ways to prevent constructions, such as scaffolds, from collapsing.

Explanation:

5 0
3 years ago
What information is usually gathered during vehicle crash tests?
aleksley [76]
Time, distance, damage
7 0
3 years ago
This test should be performed on all cord sets, receptacles that aren't part of a building or structure's permanent wiring, and
vova2212 [387]

Answer:

A continuity test

Explanation:

A continuity test is used to verified that current will flow in an electrical circuit, it performed by placing a small voltage across the chosen path. continuity test ensure that the equipment grounding conductor is electrically continuous and this test is perform on all the cord sets, receptacles that aren't part of a building or structure's permanent wiring, and cord-and-plug connected equipment required to be grounded. example of equipment used in testing current flow in continuity test are Analog multi-meter, voltage/continuity tester etc.

Continuity test and terminal connection test are the two test required by OSHA on all electrical equipment

8 0
3 years ago
A group of students launches a model rocket in the vertical direction. Based on tracking data, they determine that the altitude
Fofino [41]

Answer:

u = 260.22m/s

S_{max} = 1141.07ft

Explanation:

Given

S_0 = 89.6ft --- Initial altitude

S_{16.5} = 0ft -- Altitude after 16.5 seconds

a = -g = -32.2ft/s^2 --- Acceleration (It is negative because it is an upward movement i.e. against gravity)

Solving (a): Final Speed of the rocket

To do this, we make use of:

S = ut + \frac{1}{2}at^2

The final altitude after 16.5 seconds is represented as:

S_{16.5} = S_0 + ut + \frac{1}{2}at^2

Substitute the following values:

S_0 = 89.6ft       S_{16.5} = 0ft     a = -g = -32.2ft/s^2    and t = 16.5

So, we have:

0 = 89.6 + u * 16.5 - \frac{1}{2} * 32.2 * 16.5^2

0 = 89.6 + u * 16.5 - \frac{1}{2} * 8766.45

0 = 89.6 + 16.5u-  4383.225

Collect Like Terms

16.5u = -89.6 +4383.225

16.5u = 4293.625

Make u the subject

u = \frac{4293.625}{16.5}

u = 260.21969697

u = 260.22m/s

Solving (b): The maximum height attained

First, we calculate the time taken to attain the maximum height.

Using:

v=u  + at

At the maximum height:

v =0 --- The final velocity

u = 260.22m/s

a = -g = -32.2ft/s^2

So, we have:

0 = 260.22 - 32.2t

Collect Like Terms

32.2t = 260.22

Make t the subject

t = \frac{260.22}{ 32.2}

t = 8.08s

The maximum height is then calculated as:

S_{max} = S_0 + ut + \frac{1}{2}at^2

This gives:

S_{max} = 89.6 + 260.22 * 8.08 - \frac{1}{2} * 32.2 * 8.08^2

S_{max} = 89.6 + 260.22 * 8.08 - \frac{1}{2} * 2102.22

S_{max} = 89.6 + 260.22 * 8.08 - 1051.11

S_{max} = 1141.0676

S_{max} = 1141.07ft

Hence, the maximum height is 1141.07ft

8 0
3 years ago
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