Ask question

Ask question

All categories

3 years ago

10

list out main types of material used in design and Manufacture of product give one example for each in engineering application ?

1 answer:

cluponka [151]3 years ago

7 0

One of the types of product design is interface design. Another type of product design is called visual product design.

You might be interested in

Why is it called field effect transistor

Mrac [35]

Answer:

The field-effect transistor (FET) is a type of transistor which uses an electric field to control the flow of current.

FET is named field effect transistor as field effect is producing, but in BJT also field effect will produce. :)

5 0

3 years ago

A liquid stream containing 52.0 mole% benzene and the balance toluene at 20.0°C is fed to a continuous single-stage evaporator a

OLga [1]

Answer:

Operating Pressure P = 793.716 mmHg

Y_Benzene y1 = 0.541

Explanation:

Given that;

liquid phase leaving the evaporator = 32.5 mole%

Equi Temp T = 99.0°C = 99 + 273.15 = 372.15 K

Now let 1 and 2 represent Benzene and Toluene respectively.

Antoine's Constant for these components are;

COMPONENETS A B C

Benzene 1 4.72583 1660.652 -1.461

Toluene 2 4.07827 1343.943 -53.773

Antoine's equation is expressed as;

Ps = 10^(A - (B/(T+C)))

Ps is in Bar and T is in Kelvin

so

P1s = 10^( 4.72583 - (1660.652/(372.15 - (-1.461)))) = 1.7617 Bar

P2s = 10^( 4.07827 - (1343.943/(372.15 - (-53.773)))) = 0.7195 Bar

now here, liquid leaving and vapor are both in equilibrium

composition of liquid leaving are;

X1 = 32.5% = 0.325

X2 = 1 - X1 = 1 - 0.325 = 0.675

Now

Raoult's Law is expressed as;

p × y1=x1 × pis for all components

So for Benzene ; p × y1=x1 × p1s ------let this be equation 1

for Toluene ; p × y2=x2 × p2s ------let this be equation 2

lets add equ 1 and 2

p × y1=x1 × p1s + p × y2=x2 × p2s

p(y1 + y2) = x1 × p1s + x2 × p2s

buy y1 + y2 = 1

therefore we substitute

p(1) = 0.325 × 1.7617 + 0.675 × 0.7195 = 1.0582 Bar

we know that 1 Bar = 750.062 mmHg

so p = 1.0582 × 750.062

p = 793.716 mmHg

Also from equation 1

p × y1=x1 × p1s

y1 = (x1 × p1s) / p

y1 = (0.325 × 1.7617) / 1.0582

y1 = 0.541

Therefore;

Operating Pressure P = 793.716 mmHg

Y_Benzene y1 = 0.541

5 0

3 years ago

one airline limits the size of carry-on luggage to a volume of 40,000 cm. A passenger has a carry-on that has an area of 1,960 c

PolarNik [594]

<u>No, since the volume of the passenger's luggage ( 45,080 cm³) exceeds the allotted volume for carry-on luggages (40,000 cm³).</u>

Explanation:

<h2>Given:</h2>

Acceptable volume = 40,000 cm³

Area of luggage = 1,960 cm²

Height of luggage = 23 cm

<h2>Question:</h2>

Is the passenger's luggeage ok to carry onto the airplane

<h2>Equation:</h2>

V = l x w x h

or we can use

V = A x h

Since A = l x w

where: V - volume

A - area

l - length

w - width

h - height

<h2>Solution:</h2>

V = A x h

V = ( 1,960 cm²)(23 cm)

V = 45,080 cm³

45,080 cm³ is greater than the acceptable volume 40,000 cm³

<h2>Final Answer:</h2><h3><u>No, since the volume of the passenger's luggage ( 45,080 cm³) exceeds the allotted volume for carry-on luggages (40,000 cm³).</u></h3><h3 />

7 0

3 years ago

Calculate the resolved shear stress on the (111) 01%1 slip system of a unit cell in an FCC nickel single crystal if a stress of

abruzzese [7]

I have attached an image showing the shear stresses and direction.

Answer:

Resolved shear stress = 5.6MPa

Explanation:

From the diagram attached,

Cos λ = [(0,-1,1)•(0,0,1)]/[(√(0^2 + (-1)^2 + 1^2)) + (√(0^2 + 0^2 + 1^2))]

= 1/(√2 x√1) = 1/√2

Also, Cos Φ = [(1,1,1)•(0,0,1)]/[(√(1^2 + 1^2 + 1^2)) + (√(0^2 + 0^2 + 1^2))]

= 1/(√3 x√1) = 1/√3

So resolved shear stress (τ resolved) = 13.7 x (1/√2) x (1/√3) = 13.7 x (1/√6) = 5.593 or approximately 5.6MPa

4 0

3 years ago

A series RLC circuit consists of a 100 W resistor, a 0.15 H inductor, and a 30 µF capacitor. It is attached to a 120 V/60 Hz pow

lisov135 [29]

Answer:

yeah basically

Explanation:

3 0

3 years ago