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2 years ago

8

Which answer best describes the relationship between the left-hand and right-hand panels in both File Explorer and Finder?

1 answer:

Art [367]2 years ago

4 0

Answer: I think The left-hand panel shows like a high level list of folders. And Right-hand panel shows the contents of selected folder.

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Reasons for racking back on a wall

zmey [24]

Answer:

Racking is the term used for when buildings tilt as their structural components are forced out of plumb. This is most commonly caused by wind forces exerting horizontal pressure, but it can also be caused by seismic stress, thermal expansion or contraction, and so on.

Explanation:

3 0

3 years ago

The function below takes a two parameters: a list called a_list and a value called a_value. Complete the function to first check

Alik [6]

Explanation:

def checklist(a_list, a_value):// def //used to name a function, the //arguments being passed into the //functions are a_list and a_value

if a_value in list://if statement to

//check if it's in the list or not

print("")//print statement to do

//nothing

else://else statement for if the

//a_value is in a_list

a_list.append(a_value)//this adds

//the value to the list

5 0

3 years ago

Tech A says that the difference between stored pulse width and the actual pulse width required to keep the mixture at the correc

Levart [38]

It has to be C. hope that helps

7 0

3 years ago

Read 2 more answers

Find Ix, Iy, and J for the following shapes. In addition, find the radius of gyration (r) with respect to the x axis and y axis

k0ka [10]

Answer: steals ten points

Explanation:

8 0

3 years ago

A 3.0-m wide rectangular asphalt channel discharges 33.84 m^3/s of water with a depth of 2.0 m. What is the head loss in 100 m l

BaLLatris [955]

Answer:

Head loss in 100 m length equals 1.00 m.

Explanation:

The head loss in an open channel is calculated using manning's equation as follows

$Q=\frac{1}{n}\frac{A^{5/3}}{P^{2/3}}S_{f}^{1/2}$

For a asphalt rectangular channel we have

Area of flow = $3.0\times 2.0 = 6m^{2}$

Wetted Perimeter = $3.0+2\times 2.0=7.0m$

manning's roughness coefficient = 0.016

Applying values in the above equation we get

$33.84=\frac{1}{0.016}\times \frac{6^{5/3}}{7^{2/3}}S_{f}^{1/2}\\\\\therefore S^{1/2}_{f}=0.1\\\\\therefore S_{f}=0.01$

Now we know that

$S_{f}=\frac{H_{L}}{L}\\\\\therefore H_{l}=0.01\times 100m=1.00m$

8 0

3 years ago