Which one?? Sorry for inconvenience
The average commute for 95% of the students is between 19.0 and 4.2 miles.
The average distance is 19 miles.
Therefore, the standard deviation is 4.2 miles.
A) 2.7 = 19 - a(4.2)
where;
a deviates from the mean by a certain number of standard deviations. Thus;
a = (19 - 2.7) ÷ 4.2
a = 3
In a normal distribution, 3 standard deviations from the mean indicate that 95% of the data falls within that range.
B) The data are 2 standard deviations apart from the mean at the 95% confidence level. Thus;
CI = 19 ± 2(4.2)
CI = (18 - 10.2) OR (18 + 10.2)
CI = (7.8, 28.2)
Learn more about confidence intervals at
brainly.com/question/17097944
#SPJ4
Answer:
x=0
I used phone math!!!!!!!!
