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gladu [14]
3 years ago
3

An element has two naturally occurring isotopes. one has an abundance of 37.40% and an isotopic mass of 184.953 amu, and the oth

er has an abundance of 62.60% and a mass of 186.956 amu. what is the atomic weight of the element?
Physics
2 answers:
garri49 [273]3 years ago
5 0

The atomic weight of an element depends on masses of its isotopes and their abundance.

The mass and abundance of first isotope is 184.953 amu and 37.40% respectively and that of second isotope is 186.956 amu and 62.60% respectively.

The atomic weight of element can be calculated using the following formula:

Atomic weight=% isotope-1× mass (isotope-1)+% isotope-2× mass (isotope-2)

Putting the values,

Or,  

Therefore, atomic weight of the element is 186.207 amu.

icang [17]3 years ago
3 0

The atomic weight of an element depends on masses of its isotopes and their abundance.

The mass and abundance of first isotope is 184.953 amu and 37.40% respectively and that of second isotope is 186.956 amu and 62.60% respectively.

The atomic weight of element can be calculated using the following formula:

Atomic weight=% isotope-1× mass (isotope-1)+% isotope-2× mass (isotope-2)

Putting the values,

Atomic weight=(\frac{37.40}{100})(184.953 amu)+(\frac{62.60}{100})(186.956 amu)

Or, Atomic weight =(69.172+117.034)amu=186.207 amu

Therefore, atomic weight of the element is 186.207 amu.


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Explanation:

Given that,

Area of plates = 0.40 m²

Charge q=7.08\times10^{-10}\ C

Distance = 4.0 cm

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Using for formula of electric field

E=\dfrac{2q}{2\epsilon_{0}A}

Where, q = charge

A = area

Put the value into the formula

E=\dfrac{7.08\times10^{-10}}{8.85\times10^{-12}\times0.40}

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We need to calculate the potential difference between the plates

Using formula of potential difference

V=E\times d

Where, E = electric field

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Put the value into the formula

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V=8\ V

Hence, The potential difference between the plates is 8 V.

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Answer:

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Explanation:

Cho các dữ liệu sau đây;

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Áp suất cuối cùng = 5 * 10⁴ = 50000 Pa

Để tìm tập mới hoặc tập cuối cùng, chúng ta sẽ sử dụng định luật Boyle;

Để tìm tập mới V2, chúng tôi sẽ sử dụng định luật Boyles.

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Về mặt toán học, định luật Boyles được đưa ra bởi;

PV = K

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Thay vào phương trình, ta có;

10000 * 10 = 50000V_{2}

100000 = 50000V_{2}

V_{2} = \frac {100000}{50000}

V_{2} = 2

Thể tích cuối cùng, V2 = 2 L

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