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Studentka2010 [4]
3 years ago
14

A plastic rod is charged to -12 nC by rubbing. a) Have electrons been added or protons removed? Explain! b) How many electrons h

ave been added or protons removed?
Physics
1 answer:
klasskru [66]3 years ago
8 0

Answer:

(a) electrons being added.

(b) 7.5 × 10¹⁰

Explanation:

(a)

The plastic rod acquires a charge of -12 nC which means it contains more negative charge.

Thu, the electrons have been added to the rod. Removing protons are very difficult as they are in the nucleus and are bind by nuclear forces. Thus, by rubbing, electrons are transferred and thus the rod become negatively charged which means that the electrons being added.

(b)

The total charge = -12 nC

Also,

1 nC = 10⁻⁹ C

So,

Charge = -12 × 10⁻⁹ C

Charge on electron = -1.6 × 10⁻¹⁹ C

<u>So, number of electrons transferred = -12 × 10⁻⁹ C / -1.6 × 10⁻¹⁹ C = 7.5 × 10¹⁰ </u>

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Crank

The concept of Archimedes' principle is that an object immersed in a fluid is buoyed up by a force equal to the weight of the fluid displaced by the object. The fluid displaced has a weight W = mg, where g is acceleration due to gravity. Therefore, the weight of the displaced fluid can be expressed as W = ρVg.

8 0
3 years ago
The area of the piston to the master cylinder in a hydraulic braking system of a car is 0.4 square inches. If a force of 6.4 lb
Anit [1.1K]

Answer:

The force applied on one wheel during braking = 6.8 lb

Explanation:

Area of the piston (A) = 0.4 in^{2}

Force applied on the piston(F) = 6.4 lb

Pressure on the piston (P) = \frac{F}{A}

⇒ P = \frac{6.4}{0.4}

⇒ P = 16 \frac{lb}{in^{2} }

This is the pressure inside the cylinder.

Let force applied on the brake pad = F_{1}

Area of the brake pad (A_{1})= 1.7 in^{2}

Thus the pressure on the brake pad (P_{1}) =  \frac{F_{1} }{A_{1} }

When brake is applied on the vehicle the pressure on the piston is equal to pressure on the brake pad.

⇒ P = P_{1}

⇒ 16 = \frac{F_{1} }{A_{1} }

⇒ F_{1} = 16 × A_{1}

Put the value of A_{1} we get

⇒ F_{1} = 16 × 1.7

⇒ F_{1} = 27.2 lb

This the total force applied during braking.

The force applied on one wheel = \frac{F_{1} }{4} = \frac{27.2}{4} = 6.8 lb

⇒ The force applied on one wheel during braking.

7 0
3 years ago
Pls tell the answer asap
Rzqust [24]
The maximum force acts between B and C as the graph is steepest showing maximum deceleration
5 0
3 years ago
A truck exerts 2700 N of force on a car that is stuck in the mud, and does not move. How much work has the truck performed?
vova2212 [387]

Answer:

zero

Explanation:

although force was applied as long as there's no movement ,no work has been done

mathematically;work=force×distance

work=2700×0

work=0J

hope I helped

please like and Mark as brainliest

5 0
4 years ago
When astronauts travel to the moon, their bodies experience a lower gravitational pull than on Earth. Which type of pull are the
postnew [5]
They are experiencing the pull of leaving the atmosphere

3 0
4 years ago
Read 2 more answers
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