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melomori [17]
3 years ago
5

The force of gravity acting on a child's mass on earth is 490 newtons. what's the child's mass?

Physics
2 answers:
UNO [17]3 years ago
6 0
F = m • a

What we know:
- Gravity: 9.8 m/s
- Force: 490 N

Equation derived:
m = F/a
m = 490/9.8
= 50 kg
disa [49]3 years ago
6 0
50 kg because e = mc2

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The gravitational force of a star on an orbiting planet 1 is f1. planet 2, which is four times as massive as planet 1 and orbits
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3 years ago
2) A tomato is launched upwards with a velocity of 27 m/s. What is its height after 2.1 seconds in the air?
olga_2 [115]

The height of the tomato in air after 2.1 seconds is 78.31 m.

<h3 /><h3>What is height?</h3>

Height can be defined as vertical distance either between the top and bottom of something or between a base and something above it.

To calculate the height of the tomato after 2.1 seconds, we use the formula below.

Formula:

  • H = ut+gt²/2............. Equation 1

Where:

  • H = Height of the tomato
  • u = Initial velocity = 27 m/s
  • g = Acceleration due to gravity = Constant = 9.8 m/s²
  • t = 2.1 seconds

Substitute these values into equation 1

  • H = (27×2.1)+(9.8×2.1²)/2
  • H = 56.7+21.609
  • H = 78.31 m

Hence, the height of the tomato after 2.1 seconds is 78.31 m.

Learn more about height here: brainly.com/question/28122539

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8 0
1 year ago
In an isochoric process, the pressure in a system changes from 10 kPa to 20 kPa at V= 5m3. Calculate the work done in this proce
Elodia [21]

Answer:

work done in the process is 0 J.

Explanation:

Given :

Initial pressure of system , p_i=10\ kPa.

Final pressure of system , p_f=20\ kPa.

Volume of system , V=5\ m^3.

We know, In thermodynamics work done is defined as :

W=P\Delta V

Here , P is pressure and \Delta V is change in volume.

Now, coming back to question , it state that the process is isochoric .

Therefore, change in volume , \Delta V=0.

Putting value of \Delta V=0 in above equation we get ,

W = 0 J.

Therefore , work done in this process is 0 J.

Hence, this is the required solution.

4 0
3 years ago
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