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klasskru [66]
3 years ago
7

What kind of wave is each of the following? The sound of one whale calling another whale under water. A pulse sent down a stretc

hed rope by snapping one end of it. The vibrations in a guitar string.
Physics
1 answer:
faust18 [17]3 years ago
4 0

Answer:

The sound of one whale calling another whale under water is SOUND

WAVE.

B. A pulse sent down a stretched rope by snapping one end of it is a TRANSVERSE WAVE

C. The vibrations in a guitar string is LONGITUDINAL WAVE.

Explanation:

The sound of one whale calling another whale under water is SOUND WAVE because sound waves is a form of vibration that causes movement of energy and transport it in a medium. These consists of different compressions, vibrations of particles and it is a Longitudinal wave.

A pulse sent down a stretched rope by snapping one end of it is a TRANSVERSE WAVE because Crest and troughs are formed when pulse is sent down a stretched rope by snapping one end and transverse wave is a wave in which it's particles in a medium then transport itself in a direction which is usually perpendicular to the directions of the wave.

The vibrations in a guitar string is LONGITUDINAL WAVE because guitar strings causes a vibration and vibrates in air medium which result in the formation of compressions, vibrations and rarefactions in the wave of sound through the air medium.

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Answer:

The bin moves 0.87 m before it stops.

Explanation:

If we analyze the situation and apply the law of conservation of energy to this case, we get:

Energy Dissipated through Friction = Change in Kinetic Energy of Bin (Loss)

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where,

F = Frictional Force = μR    

but, R = Normal Reaction = Weight of Bin = mg

Therefore, F = μmg

Hence, the equation becomes:

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Vf = Final Velocity = 0 m/s (Since, bin finally stops)

Vi = Initial Velocity = 1.6 m/s

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g = 9.8 m/s²

d = distance moved by bin before coming to stop = ?

Therefore,

d = (0.5)[(1.6 m/s)² - (0 m/s)²]/(0.15)(9.8 m/s²)

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5 0
3 years ago
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When you hit a bump every 0.9 seconds.
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Answer:

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