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klasskru [66]
3 years ago
7

What kind of wave is each of the following? The sound of one whale calling another whale under water. A pulse sent down a stretc

hed rope by snapping one end of it. The vibrations in a guitar string.
Physics
1 answer:
faust18 [17]3 years ago
4 0

Answer:

The sound of one whale calling another whale under water is SOUND

WAVE.

B. A pulse sent down a stretched rope by snapping one end of it is a TRANSVERSE WAVE

C. The vibrations in a guitar string is LONGITUDINAL WAVE.

Explanation:

The sound of one whale calling another whale under water is SOUND WAVE because sound waves is a form of vibration that causes movement of energy and transport it in a medium. These consists of different compressions, vibrations of particles and it is a Longitudinal wave.

A pulse sent down a stretched rope by snapping one end of it is a TRANSVERSE WAVE because Crest and troughs are formed when pulse is sent down a stretched rope by snapping one end and transverse wave is a wave in which it's particles in a medium then transport itself in a direction which is usually perpendicular to the directions of the wave.

The vibrations in a guitar string is LONGITUDINAL WAVE because guitar strings causes a vibration and vibrates in air medium which result in the formation of compressions, vibrations and rarefactions in the wave of sound through the air medium.

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The solubility of gases in liquids increases with the increase in pressure.
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Light of wavelength 560 nm passes through a slit of width 0. 170 mm. (a) the width of the central maximum on a screen is 8. 00 m
faltersainse [42]

The distance between slit and the screen is 1.214m.

To find the answer, we have to know about the width of the central maximum.

<h3>How to find the distance between slit and the screen?</h3>
  • It is given that, wavelength 560 nm passes through a slit of width 0. 170 mm, and the width of the central maximum on a screen is 8. 00 mm.
  • We have the expression for slit width w as,

                           w=\frac{2*wavelength*d}{a}

where, d is the distance between slit and the screen, and a is the slit width.

  • Thus, distance between slit and the screen is,

                           d=\frac{w*a}{2*wavelength} =\frac{8*10^{-3}*0.17*10^{-3}}{560*10^{-9}*2} \\\\d=1.214m

Thus, we can conclude that, the distance between slit and the screen is 1.214m.

Learn more about the width of the central maximum here:

brainly.com/question/13088191

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3 0
1 year ago
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Answer:

charcoal is the correct answer

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3 years ago
The greater the of an object the more force is needed to cause acceleration
d1i1m1o1n [39]

the greater the <u>mass</u> of an object the more force is needed to cause acceleration



8 0
3 years ago
The volume occupied by a sample of gas is 480 mL when the pressure is 115 kPa.What pressure must be applied to the gas to make i
balandron [24]

Answer:

The answer is

<h2>84.9 kPa</h2>

Explanation:

Using Boyle's law to find the final pressure

That's

P_1V_1 = P_2V_2

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the final pressure

P_2 =  \frac{P_1V_1}{V_2}

From the question

P1 = 115 kPa

V1 = 480 mL

V2 = 650 ml

So we have

P_2 =  \frac{115000 \times 480}{650}  = \frac{55200000}{650}  \\  = 84923.076923...

We have the final answer as

<h3>84.9 kPa</h3>

Hope this helps you

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3 years ago
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