Answer:
The final velocity of her partner is approximately -1.04 m/s or 1.04 m/s in the opposite direction to her direction of motion
Explanation:
The given parameters are;
The mass of the man, m₁ = 65 kg
The mass of the woman, m₂ = 45 kg
Taking the relative initial velocity of the man and the woman as 0 m/s, we have;
The initial velocity of the man, v₁₁ = 0 m/s
The initial velocity of the man, v₁₂ = 0 m/s
The final velocity of the woman, v₂₂ = 1.5 m/s
The final velocity of the man = v₂₁
Therefore, we have, by the conservation of momentum principle;
The total initial momentum = The total final momentum
Which gives;
m₁ × v₁₁ + m₂ × v₁₂ = m₁ × v₂₁ + m₂ × v₂₂
Substituting the known values;
65 × 0 + 45 × 0 = 65 × v₂₁ + 45 × 1.5
∴ 65 × v₂₁ + 45 × 1.5 = 0
45 × 1.5 = - 65 × v₂₁
v₂₁ = 45 × 1.5/(-65) ≈ -1.04 m/s
The final velocity of the man, her partner = v₂₁ ≈ -1.04 m/s.
