Answer:
A concave mirror has a focal length of. 10.0 cm. What is its radius of curvature? ... 20.0 cm. 62. An object located 18 cm from a convex mirror produces a virtual image 9 ... cm. 75 cm. 66. Find the image position and height for the object shown in ... 1 block 1.0 cm. Vertical scale: 2 blocks 1.0 cm. F. I1 hi. 1.0 cm di. 2.7 cm. O1.
Explanation:
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11 grams were released.think it help
Answer:
true
Explanation:
the wavelength of AM radio is 10 m whereas FM has 1 m
Answer:
a) = 10.22 rad/s
b) = 0.35 m
Explanation:
Given
Mass of the particle, m = 1.1 kg
Force constant of the spring, k = 115 N/m
Distance at which the mass is released, d = 0.35 m
According to the differential equation of s Simple Harmonic Motion,
ω² = k / m, where
ω = angular frequency in rad/s
k = force constant in N/m
m = mass in kg
So,
ω² = 115 / 1.1
ω² = 104.55
ω = √104.55
ω = 10.22 rad/s
If y(0) = -0.35 m and we want our A to be positive, then suffice to say,
The value of coefficient A in meters is 0.35 m
Answer:
<h2>The pin's final velocity is 5m/s</h2>
Explanation:
Step one:
given data
mass of ball m1=5kg
initial velocity of ball u1=10m/s
mass of pin m2=2kg
initial velocity of pin u2= 0m/s
final velocity of ball v2=8m/s
final velocity of pin v2=?
Step two:
The expression for elastic collision is given as
m1u1+m2u2=m1v1+m2v2
substituting we have
5*10+2*0=5*8+2*v2
50+0=40+2v2
50-40=2v2
10=2v2
divide both sides by 2
v2=10/2
v2=5m/s
The pin's final velocity is 5m/s
