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3 years ago

A truck hits a brick wall with a force of 100000 kg ms² the truck comes to a stop in 0.5 s what is the impulse

Physics

1 answer:

vladimir1956 [14]3 years ago

4 0

Answer:

Impulse = 50,000 J

Explanation:

Given: force = 100,000 kg ms^2 or N; time = 0.5 s

Unknown: impulse = ?

Equation: impulse = (force)(time)

Substitute: impulse = (100,000 kg ms^2 or N)(0.5 s)

Solution: impusle = 50,000 kg ms^2 or J

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Answer:

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2 years ago

After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 53.0 cm . The explorer finds that

larisa86 [58]

Answer:

12.4 m/s²

Explanation:

L = length of the simple pendulum = 53 cm = 0.53 m

n = Number of full swing cycles = 99.0

t = Total time taken = 128 s

T = Time period of the pendulum

g = magnitude of gravitational acceleration on the planet

Time period of the pendulum is given as

$T = \frac{t}{n}$

$T = \frac{128}{99}$

T = 1.3 sec

Time period of the pendulum is also given as

$T = 2\pi \sqrt{\frac{L}{g}}$

$1.3 = 2(3.14) \sqrt{\frac{0.53}{g}}$

g = 12.4 m/s²

4 0

3 years ago

The photeselestric effect is observed when light of a sufficiently high frequency is focused onto a polished metal surface, emit

Helga [31]

Answer:

$3.4\cdot 10^{-19} J$

Explanation:

In order to convert the work function of cesium from electronvolts to Joules, we must use the following conversion factor:

$1 eV = 1.6 \cdot 10^{-19} J$

In our problem, the work function of cesium is

$E=2.1 eV$

so, we can convert it into Joules by using the following proportion:

$1 eV : 1.6\cdot 10^{-19} J = 2.1 eV : x\\x=\frac{(1.6\cdot 10^{-19} J)(2.1 eV)}{1 eV}=3.4\cdot 10^{-19} J$

8 0

3 years ago

A light ray incident on a block of glass makes an incident angle of 50.0° with the normal to the surface. The refracted ray in t

Vladimir [108]

Answer:

The index of refraction of the glass is 1.3

Explanation:

Given data:

i = incident angle = 50°

r = refracted angle = 36.1°

The index of refraction according Snell´s law is:

$n=\frac{1*sini}{sinr} =\frac{1*sin50}{sin36.1} =1.3$

4 0

3 years ago

Methods to reduce the frictional force between the an object and surface which it is in contact.

telo118 [61]

Use of lubricant
Use of ball bearers
Use of streamlined body
Use of graphite

7 0

3 years ago