Answer:
to know what that specif animal or thing does in the food chain
Explanation:
Answer:
K = -½U
Explanation:
From Newton's law of gravitation, the formula for gravitational potential energy is;
U = -GMm/R
Where,
G is gravitational constant
M and m are the two masses exerting the forces
R is the distance between the two objects
Now, in the question, we are given that kinetic energy is;
K = GMm/2R
Re-rranging, we have;
K = ½(GMm/R)
Comparing the equation of kinetic energy to that of potential energy, we can derive that gravitational kinetic energy can be expressed in terms of potential energy as;
K = -½U
Answer:
Match the scenario to the type of movement that caused it.
Ted is in his home when a strong vibration occurs that shakes the dishes out of his cupboards.
Whitney feels a slight tremor three weeks subsequent to an earthquake in a nearby town.
Sam pulls off the side of a road after feeling the road move unexpectedly while driving to work.
Foreshock
Mainshock
Aftershock
Explanation: PLZZ HELP ME I NEED TO PASS STEM!
Answer:
Explanation:
Given that,
Mass of ball m = 2kg
Ball traveling a radius of r1= 1m.
Speed of ball is Vb = 2m/s
Attached cord pulled down at a speed of Vr = 0.5m/s
Final speed V = 4m/s
Let find the transverse component of the final speed using
V² = Vr²+ Vθ²
4² = 0.5² + Vθ²
Vθ² = 4²—0.5²
Vθ² = 15.75
Vθ =√15.75
Vθ = 3.97 m/s.
Using the conservation of angular momentum,
(HA)1 = (HA)2
Mb • Vb • r1 = Mb • Vθ • r2
Mb cancels out
Vb • r1 = Vθ • r2
2 × 1 = 3.97 × r2
r2 = 2/3.97
r2 = 0.504m
The distance r2 to the hole for the ball to reach a maximum speed of 4m/s is 0.504m
The required time,
Using equation of motion
V = ∆r/t
Then,
t = ∆r/Vr
t = (r1—r2) / Vr
t = (1—0.504) / 0.5
t = 0.496/0.5
t = 0.992 second
The radius of a nucleus of hydrogen is approximately
, while we can use the Borh radius as the distance of an electron from the nucleus in a hydrogen atom:
The radius of a dime is approximately
: if we assume that the radius of the nucleus is exactly this value, then we can find how far is the electron by using the proportion
from which we find
So, if the nucleus had the size of a dime, we would find the electron approximately 500 meters away.
