For the answer to the question above, I'll show the solution to my answers
moles C = 82.66 g/ 12.0111 g/mol=6.882
<span>moles H = 17.34 g/ 1.008 g/mol=17.20 </span>
<span>17.20/ 6.882 =2.5 => H </span>
<span>6.882 / 6.882 = 1 => C </span>
<span>to get whole numbers multiply by 2 </span>
<span>C2H5 ( empirical formula Molar mass = 29.062 g/mol) </span>
<span>n = pV/RT = 0.732 x 0.158 L/ 0.08206 x 298 K= 0.00473 </span>
<span>molar mass = 0.275/ 0.00473 =58.1 g/mol </span>
<span>58.1 / 29.062 = 2 </span>
<span>multiply by two the empirical formula </span>
<span>C4H10</span>
Answer:
Nonmetal + Nonmetal —> covalent compound (usually)
Explanation:
Covalent compounds are formed when two nonmetals react with each other.
look at the chemical tables. but i believe it is A
<h2>
Answer: 6 moles</h2>
<h3>
Explanation:</h3>
3 H₂ + N₂ → 2 NH₃
↓ ↓
4 mol 3 mol
Since the moles of N₂ is the smaller of the two reactants, then N₂ is the limiting factor (the reactant that will decide how much ammonia is produced since it has the smaller amount of moles). ∴ we have to use it in calculating the number of moles of ammonia
The mole ratio of N₂ to NH₃ based on the balanced equation is 1 to 2.
∴ the moles of NH₃ = moles of N₂ × 2
= 3 moles × 2
= 6 moles
Should be 1.8L.
2 moles of hydrogen react with 1 mole of oxygen. If 2 moles of hydrogen is 3.6L, 1 mole of oxygen should be 1.8L.
