Answer:
53.93 g Ag
Explanation:
3.011x1023 atoms Ag x <u> 1 mole Ag </u> x <u>107,8683 grams</u> =
6.022x
atoms 1 mole Ag
use the periodic table fo find Ag atomic mass and use Avogadro´s number
Answer:
2,53x10⁻³ moles of NaOH
Explanation:
The reactions of a diprotic acid with NaOH are:
H₂X + NaOH → HX⁻ + H₂O + Na⁺
HX⁻ + NaOH → X²⁻ + H₂O + Na⁺
Where the complete first reaction gives the first equivalence point and the complete second reaction gives the second equivalence point.
The total volume spent of NaOH to reach the second equivalence point is:
7,00mL + 14,07mL = 21,07 mL = <em>0,02107L</em>
As molar concentration of NaOH is 0,120M, the moles used to reach the second equivalence point are:
0,02107L×(0,120mol/L) = <em>2,53x10⁻³ moles of NaOH</em>
I hope it helps!
The limiting reactant here is P4O10 . The percent yield of the product is caculated as 33.3%.
<h3>What is the limiting reactant?</h3>
The limiting reactant is the reactant that is in a minute quantity.
Number of moles of P4O10 = 85.5 g/284 g/mol = 0.3 moles
Number of moles of H2O = 74.9 g / 18 g/mol = 4.2 moles
From the reaction equation;
1 mole of P4O10 reacts with 6 moles of H2O
x moles of P4O10 reacts with 4.2 moles of H2O
x = 0.7 moles
Hence, P4O10 is the limiting reactant.
1 mole of P4O10 yields 4 moles of H3PO4
0.3 moles of P4O10 yields
0.3 moles * 4/1 = 1.2 moles
Mass of the H3PO4 = 1.2 moles * 98 g/mol = 117.6 g
Percent yield = 39.2 g/117.6 g * 100/1 = 33.3 %
Learn more about limiting reactant:brainly.com/question/14225536
Answer:
21.52° C
Explanation:
From the given information:
mass of the liquid water = 70.0 mL
Initial temperature = 20°C
mass of the ice = 5.0 g
temperature of ice = 0.0°C
Using the calorimetric function:
heat lost by water = heat gained by ice.
mass of water × specific heat of water (s) × ΔT = mass of ice × specific heat of ice (s) × ΔT + n (ΔH_fusion}
⇒ 70 × 4.184 × (28 -x) = 5 × 2.108(x - 0) + 
× 6.01 × 10³
By solving the above equation,
x = 21.52° C
Answer: the color of light shining on the photocell.
Explanation:
1) In an experiment there are two kind of variables: independent variables and dependent variables.
2) The independent variable is the one that can be changed or manipulated. This is done because you want to learn how the changes in this variable may explain or are related to other variable (the dependent variable).
In the description of the experiment, the color of the light is being changed, by placing different color of cellophanes ove the same flashlight.
This is how, keeping the control over other possible variables (the flashlight kind and its distance from the photocell, for example) the experimenter manages to change one only variable: the color of light.
3) On the other hand, the dependent variable, is the variable that is being explained. You do not manipulate the dependent variable directly but you want to learn to what extent this dependent variable is determined by, explained by, predicted by, or simply related to, the independent variable.
In conclusion, the independent variable is the color of light.
