3 years ago

True Or False: "the baseball fans are cheering therefore a ball was hit out of the park" is an example of an inference.

Chemistry

1 answer:

GuDViN [60]3 years ago

8 0

Answer:

False

Explanation:

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How many moles are 21.67 L of NH4CI?

Gnoma [55]

Answer:

0.967mole

Explanation:

Given parameters:

Volume of NH₄Cl = 21.67L

Unknown:

Number of moles = ?

Solution:

If we assume that the volume was taken at standard temperature and pressure,

Then;

Number of moles = $\frac{volume }{22.4L}$

Number of moles = $\frac{21.67}{22.4}$ = 0.967mole

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3 years ago

The ""size"" of an atom is sometimes defined by the radius of a sphere that contains 90% of the charge density of the electrons.

vfiekz [6]

Answer:

3/2a

Explanation:

The complete step by step answer is found in the attachment

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3 years ago

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Naya [18.7K]

The answers are in the attached file

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2 years ago

Why is the inner core's state of matter different from the outer core's state of matter

Ganezh [65]

Because the inner course is a totally different thing then the outer course

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3 years ago

Methanol, ethanol, and n-propanol are three common alcohols. When 1.00 g of n-propanol (C3H7OH)is burned in air, -33.4 kJ of hea

Inga [223]

Answer : The heat of combustion of n-propanol is 0.554 kJ/mol

Explanation :

First we have to calculate the moles of n-propanol.

$\text{Moles of n-propanol}=\frac{\text{Mass of n-propanol}}{\text{Molar mass of n-propanol}}$

Molar mass of n-propanol = 60.09 g/mole

$\text{Moles of n-propanol}=\frac{1.00g}{60.09g/mole}=0.0166mole$

Now we have to calculate the heat of combustion of n-propanol.

As, 0.0166 mole of n-propanol liberated heat of combustion = -33.4 kJ

So, 1 mole of n-propanol liberated heat of combustion = 0.0166 × (-33.4 kJ)

= 0.554 kJ/mol

Therefore, the heat of combustion of n-propanol is 0.554 kJ/mol

5 0

2 years ago