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3 years ago

4 less than a number and 9

Mathematics

1 answer:

tangare [24]3 years ago

3 0

Answer:

9x-4

Step-by-step explanation:

9x-4 4 less = -4. number = x. 9 is by x.

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Brut [27]

Answer:

-16

Step-by-step explanation:

You have to start by answering the parenthesis first then continue with the question

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3 years ago

Can I get some help Please?

MAXImum [283]

Answer:

Yes

Step-by-step explanation:

So quadratic formulas help

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2 years ago

SIMPLIFY 7x to the power of 2 + 6x + 9x to the power of 2 - 5x

Marizza181 [45]

$7x^2+6x+9x^2-5x=(7x^2+9x^2)+(6x-5x)=16x^2+x$

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3 years ago

Find the Difference. 3x + 5 - (2x + 2) How do I do this step by step?

Anna11 [10]

Answer: The correct answer is x+3

Step-by-step explanation: To find the answer you must first remove the parentheses then you combine the like terms and that how you get your answer.

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3 years ago

Read 2 more answers

Inverse laplace of [(1/s^2)-(48/s^5)]

Katen [24]

**Refresh page if you see [ tex ]**

I am not familiar with Laplace transforms, so my explanation probably won't help, but given that for two Laplace transform $F(s)$ and $G(s)$ , then $\mathcal{L}^{-1}\{aF(s)+bG(s)\} = a\mathcal{L}^{-1}\{F(s)\}+b\mathcal{L}^{-1}\{G(s)\}$

Given that $\dfrac{1}{s^2} = \dfrac{1!}{s^2}$ and $-\dfrac{48}{s^5} = -2\cdot\dfrac{4!}{s^5}$

So you have $\mathcal{L}^{-1}\left\{\dfrac{1}{s^2} - 2\cdot\dfrac{4!}{s^5}\right\} = \mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\}$

From Table of Laplace Transform, you have $\mathcal{L}\{t^n\} = \dfrac{n!}{s^{n+1}}$ and hence $\mathcal{L}^{-1}\left\{\dfrac{n!}{s^{n+1}}\right\} = t^n$

So you have $\mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\} = \boxed{t-2t^4}$ .

Hope this helps...

7 0

3 years ago