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Dmitriy789 [7]
2 years ago
5

There is 35 mg of sodium in a can of Coke. You determine it to be 28 mg. What is your percent error?

Chemistry
2 answers:
natali 33 [55]2 years ago
8 0

Answer:

The answer is

<h2>20 %</h2>

Explanation:

The percentage error of a certain measurement can be found by using the formula

P(\%) =  \frac{error}{actual \:  \: number}  \times 100\% \\

From the question

actual volume = 35 mg

error = 35 - 28 = 7

The percentage error is

P(\%) =  \frac{7}{35}  \times 100 \\  =  \frac{1}{5}  \times 100 \\  =  20

We have the final answer as

<h3>20 %</h3>

Hope this helps you

babymother [125]2 years ago
8 0

Answer:

20%

Explanation:

The formula is [ |va-ve/ve| * 100% ] where e = error and n = number.

|28-35/35| * 100

|-7/35| * 100%

|-1/5| * 100%

0.2 * 100%

20%

Best of Luck!

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Explanation:

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A solution is prepared by mixing 50.0 mL toluene (C6H5CH3 d=0.867 g/mL) with 125 mL Benzene (C6H6 d=0.874 g/mL). Assuming that t
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Answer:

mass % = 28.4%

mole fraction = 0.252

molality = 3.08 molal

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Explanation:

Step 1: Data given

Volume of toluene = 50.0 mL = 0.05 L

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Molar mass toluene = 92.14 g/mol

Volume of benzene = 125 mL = 0.125 L

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Step 2: Calculate masses

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Step 3: Calculate number of moles

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Moles benzene = 109.25 grams / 78.11 g/mol = 1.399 moles

Step 4: Calculate molarity of toluene

Molarity = moles / volume

Molarity toluene = 0.4705 moles / 0.175 L = 2.69 M

Step 5: Calculate mass % of toluene

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Step 6: Calculate mole fraction of toluene

Mole fraction toluene = Moles toluene / total number of moles

Mole fraction toluene = 0.4705 / (0.4705 + 1.399) = 0.252

Step 7: Molality of toluene

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Molality of toluene = 3.08 molal

4 0
3 years ago
A solution contains 0.60 mg/ml mn2+. what minimum mass of kio4 must me added to 5.00 ml of the solution in order to completely o
azamat
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Hence, moles of Mn²⁺ = 3 x 10⁻³ g / 54.9 g/mol = 5.46 x 10⁻⁵ mol

The balanced equation for the reaction is,
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Answer:

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