Suppose you are walking home after school. The distance from school to your home is five kilometers. On

If you are looking for a substance that will easily dissolve in water, you should look for a substance with which properties?

olga nikolaevna [1]

<span>If you are looking for a substance that will easily dissolve in water, you should look for a substance with which properties? it is b. high solubility

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5 0

3 years ago

Now put that book 5 feet in the air. What kind of energy does the book have? Explain.

erastova [34]

Answer:

Gravitational potential energy

Explanation:

The book is put 5 feet in the air, which means 5 feet above the ground. An object which is located to a certain height above the ground possesses a form of energy called gravitational potential energy, which is the energy due to the fact that the object has "potential" to transform this energy into other forms of energy (e.g. kinetic energy, if the book is released and it starts moving).

The value of the gravitational potential energy of the object is given by the formula:

$U=mgh$

where

m is the mass of the object

g is the gravitational acceleration (9.8 m/s^2)

h is the height of the book above the ground (in this case, 5 feet)

So, we see that the gravitational potential energy is proportional to both the mass and the height of the object.

8 0

4 years ago

you push with an 18-N horizontal force on a 5-kg box of coffee resting on a on a horizontal surface. the force of friction on th

KatRina [158]

The acceleration is found to be 2 m/s², final velocity after 10 seconds is 20 m/s and the final position after 10 seconds is 100 m away from the starting point.

Answer:

Explanation:

As per Newton's second law of motion, acceleration of any object is directly proportional to the net external unbalanced force acting on that object and inversely proportional to the mass of the object.

Since there are two forces acting on the box in opposite direction, the net force will be the difference of horizontal and frictional force acting on the object.

Net force = Horizontal force - Frictional force = 18 N - 8 N = 10 N.

Now, from second law of motion, $Acceleration = \frac{Net force}{Mass}$

So, acceleration = 10 N /5 kg = 2 m/s².

Since, acceleration exerted by the box is found to be 2 m/s², we can determine the final velocity of the object after 10 seconds using the first equation of motion.

v = u + at, Here v is the final velocity and u is the initial velocity which is zero for the present case. Other parameters like a is found to be 2 m/s² and time is 10 seconds.

So Final velocity v = 0+(2×10)=20 m/s.

And the final position can be determined using the second equation of motion.

s = ut+1/2at²

Final position = (0×10)+(0.5×2×10×10)= 100 m.

So the final position is 100 m.

Thus, the acceleration is found to be 2 m/s², final velocity after 10 seconds is 20 m/s and the final position after 10 seconds is 100 m away from the starting point.