The rule for this sequence is n + 3.
132 --> 135 is +3,
135 --> 138 is +3,
and 138 --> 141 is +3.
Let's use this rule until we find the 13th term.
132 (1)
135(2)
138(3)
141(4)
144(5)
147(6)
150(7)
153(8)
156(9)
159(10)
162(11)
165(12)
168(13)
168 is the 13th term in this sequence.
I hope this helps!
The answer to this question is going to be 88.53 because you shift it horizontally
Well, the cos(∅) is negative in the second and third quadrants. If you are solving for theta, you would use the inverse of the cos or arccos

take the inverse of both sides to get:
x = arccos(-2/3) now evaluate the right
x = 131.8103149 degrees
to find your second solution, subtract your reference angle from 360 degrees.
360 - 131.8103149 = 228.1896851 degrees
Now the period of cos is 2π or 360 degrees. So if you want to consider all possible solutions, you would need to add/subtract 360n to both solutions above..
Not sure if this is what you're looking for, but thought I would leave it here for you just in case... As a side note, you could do this problem in radian measurement as well.
The answer for this is 0 . 7 X 6= 42 - 42 = 0
5(6 - 4v)=v+21
30 - 20v=v+21
30-21=v+20v
9=21v both side divided by 21
9÷21=v
0,428=v