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Lapatulllka [165]
3 years ago
14

A mother pushes a baby stroller 50 meters by applying 10 newtons of force. How much work was done?

Physics
2 answers:
Alex3 years ago
5 0
A mother pushes a baby stroller 50 meters by applying 10 newtons of force. How much work was done?

Answer.- 500 joules
german3 years ago
5 0

Work is defined  as the process of causing matter to move against an opposing force. The formula for calculating it would be - force • distance. The equation for this would then be 10 (newtons) • 50 (meters) = 500 joules. Joules is the unit of measurement used to measure energy (work).

Hope this Helped :)

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A coin completes 18 spins in 12 seconds. The centripetal acceleration of the edge of the coin is 2.2 m/s2. The radius of the coi
stellarik [79]

Answer:

2.5 cm

Explanation:

Number of spins in 12 seconds = 18

Number of spins in 1 second = 18 / 12 = 1.5

Number of spins in one second is called frequency.

f = 1.5 rps

ac = 2.2 m/s^2

Let r be the radius of coin

Centripetal acceleration, ac = r x w^2

2.2 = r x ( 2 x 3.14 x 1.5) ^2

2.2 = r x 88.7364

r = 0.025 m = 2.5 cm

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Magma that cools and crystallizes on Earth's surface forms 
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The correct answer is:

D. Extrusive rocks.

The explanation:

when extrusive igneous rocks form when magma reaches the Earth's surface a volcano and cools quickly. Most extrusive (volcanic) rocks have small crystals. Examples include basalt, rhyolite, andesite, and obsidian.

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3 years ago
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Point charge A is located at point A and point charge B is at point B. Points A and B are separated by a distance r. To determin
fredd [130]

Answer:

B. The algebraic sum of the two electric potentials is determined at a distance r/2 from each of the charges, making sure to include the signs of the charges.

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Total electric potential is the sum of all the electric potential. And because electric potential is a scalar quantity you have to account for the signs.

3 0
3 years ago
A 1,500 kg car’s speed changes from 30 m/s to 15 m/s after the brakes are applied. Calculate the work done onto the car from the
HACTEHA [7]

The work done onto the car is 506,250 J

The work done on a system implies an increase in the internal energy of the system as a result of some forces acting on the system from the outside.

From the parameters given:

  • The mass of the car = 1500 kg
  • The initial speed = 30 m/s
  • The final speed = 15 m/s

The work done onto the car refers to the change in the kinetic energy (i.e. ΔK.E)

\mathbf{=\dfrac{1}{2} mv_1^2 -\dfrac{1}{2} mv_2^2}

\mathbf{=\dfrac{1}{2} m(v_1^2 - v_2^2)}

\mathbf{=\dfrac{1}{2} \times 1500 \times (30^2 - 15^2)}

= 506,250 J

Therefore, we can conclude that the work done on the car is 506,250 J

Learn more about work done here:

brainly.com/question/18762601

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