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2 years ago

A ray diagram for a refracted light ray is shown.

Physics

1 answer:

levacccp [35]2 years ago

8 0

Answer:

Refracted ray

Explanation:

Because it change direction after passing the boundary

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Which of the following produces a physical change ?

stellarik [79]

Answer:

B: leaving metal outside in the rain until rust forms an it's surface

4 0

1 year ago

A feather, a tennis ball, and a bowling ball are dropped from a high tower on

Vlada [557]

Answer:

In the absence of air resistance. I think no. D ) The bowling ball.

Hope this helps...

7 0

2 years ago

Which of the following circuits can be used to measure the resistance of the heating element, shown as a resistor in the diagram

Wewaii [24]

In order to measure the resistance in the circuit, we need to know the voltage V and the current I in the circuit, this way we can calculate the resistance using the formula:

$R=\frac{V}{I}$

In order to calculate the current, we can use an amperemeter that must be in series with the circuit, this way it will not affect the circuit.

And in order to calculate the voltage, we can use a voltmeter that must be in parallel with the resistance, this way it will not affect the circuit.

The correct option that shows an amperemeter in series and a voltmeter in parallel is the fourth option.

8 0

8 months ago

a hot iron bar is placed 100ml 22C water. the water temperature rises to 32C. how much heat did the water gain and how much heat

Sergeu [11.5K]

Answer:

Water gained: 10
Iron lost: -10

Explanation:

Given: Hot iron bar is placed 100ml 22C water, the water temperature rises to 32C

To find: How much heat the water gain, how much heat did the iron bar lost

Formula:Q = change T x C x M

Solve:

How much heat water gained

Initial heat = 22, then rose to 32. To find how much heat the water gained, simply subtract the current heat by the initial heat.

32 - 22 = 10

The water gained 10 amounts of heat.

How much heat Iron lost

Current heat = 32, then dropped to 22. To find how much heat the Iron lost, simply subtract the initial heat by the current heat.

22 - 32 = -10

The Iron lost -10 amounts of water.

4 0

3 years ago

Derive an expression for the gravitational potential energy U(r) of the object-earth system as a function of the object's distan

Drupady [299]

Answer:

$U(r)=-\frac{Gm_Emr^2}{2R^3_E}$

Explanation:

We are given that

Gravitational force= $F_g=\frac{Gm_Emr}{R^3_E}$

r=0,U(0)=0

We know that

Gravitational potential energy= $-\int F_gdr$

$U(r)=-\int\frac{Gm_Emr}{R^3_E}dr$

$U(r)=-\frac{Gm_Em}{R^3_E}\times \frac{r^2}{2}+C$

Substitute r=0 ,U(0)=0

$0=0+C$

$C=0$

Substitute the value

$U(r)=-\frac{Gm_Emr^2}{2R^3_E}$

4 0

3 years ago