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Kobotan [32]
3 years ago
7

Find the surface area of a cylinder with a base diameter of 6 yd and a height of 5 yd

Mathematics
1 answer:
Morgarella [4.7K]3 years ago
5 0
To find the top and bottom circles you use:
2(pi x r^2)
- your r (radius) is half of the diameter so 3.

To find the part around it you use:
2 x pi x r x height

Circles: 2(pi x 3^2) = 56.5487
Rectangular around: 2 x pi x 3 x 5 = 94.2478

- then add them together
56.5487 + 94.2478 = 150.7965 yards^2

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Which digit is in the tenths place of 36
Volgvan
The digit would be 0 if its just 36
3 0
2 years ago
Read 2 more answers
The rectangular field is 120 yards long and 40 yards wide. How many square yards is it’s area?
lilavasa [31]

Answer:

4800 yards wide

Step-by-step explanation:

120 x 40=4800

3 0
2 years ago
Find the area of each regular polygon. Round your answer to the nearest tenth if necessary.
tatuchka [14]

*I am assuming that the hexagons in all questions are regular and the triangle in (24) is equilateral*

(21)

Area of a Regular Hexagon: \frac{3\sqrt{3}}{2}(side)^{2} = \frac{3\sqrt{3}}{2}*(\frac{20\sqrt{3} }{3} )^{2} =200\sqrt{3} square units

(22)

Similar to (21)

Area = 216\sqrt{3} square units

(23)

For this case, we will have to consider the relation between the side and inradius of the hexagon. Since, a hexagon is basically a combination of six equilateral triangles, the inradius of the hexagon is basically the altitude of one of the six equilateral triangles. The relation between altitude of an equilateral triangle and its side is given by:

altitude=\frac{\sqrt{3}}{2}*side

side = \frac{36}{\sqrt{3}}

Hence, area of the hexagon will be: 648\sqrt{3} square units

(24)

Given is the inradius of an equilateral triangle.

Inradius = \frac{\sqrt{3}}{6}*side

Substituting the value of inradius and calculating the length of the side of the equilateral triangle:

Side = 16 units

Area of equilateral triangle = \frac{\sqrt{3}}{4}*(side)^{2} = \frac{\sqrt{3}}{4}*256 = 64\sqrt{3} square units

4 0
3 years ago
How do I find x and y
Alja [10]
X^2=3^2+7^2-*3*7cos52
x=6.083

7^2=3^2+6.08^2-2*3*6.08cosy

solving for y
y=94.71
3 0
3 years ago
What Fraction Of The Wall Did Kevin Paint?
Mila [183]

Kevin painted \frac{1}{9} of the wall.

Solution:

Fraction of the wall painted by Elena = \frac{5}{9}

Fraction of the wall painted by Matthew = \frac{3}{9}

Fraction of the wall painted by Kevin = ?

Full wall can be taken as 1.

<u>To find the wall painted by Kevin:</u>

Rest of the wall = Full wall – painted by Elena – Painted by Matthew

                          $=1-\frac{5}{9}-\frac{3}{9}

                          $=\frac{1}{1} -\frac{5}{9}-\frac{3}{9}

To make the denominator same, multiply the numerator and denominator of the first term by 9.

                          $=\frac{9}{9} -\frac{5}{9}-\frac{3}{9}

                          $=\frac{9-5-3}{9}

                          $=\frac{1}{9}

Rest of the wall = \frac{1}{9}

Hence the kevin painted \frac{1}{9} of the wall.

6 0
2 years ago
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