1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
omeli [17]
3 years ago
10

(15 POINTS)Which best describes the electric field created by a positive charge?

Physics
2 answers:
inysia [295]3 years ago
7 0

Answer: The correct option is "Its rays point away from the charge".

Explanation:

Electric field is the surrounding of the charge in which the electric force can be experienced.

The expression of the electric force in terms of charge and the electric field is as follows;

F=qE

Here, q is the charge and E is the electric field.

The direction of the electric field of a positive charge is away from the charge.

The direction of the electric field of a negative charge is towards the charge.

Therefore, the electric field created by a positive charge describes its rays point towards the charge.

MrRa [10]3 years ago
6 0
I would go with C. It's ray point away from the charge.
You might be interested in
What runs all the way around the house but never moves?
amm1812
<span>A fence runs all the way around the house but never moves.</span>
6 0
3 years ago
Read 2 more answers
When atoms bond together, they make:
Aneli [31]
When atoms bond together they make molecules.
all the best
6 0
3 years ago
Read 2 more answers
When conduction electrons pass through a device with resistance, which describes their energy?
Aleksandr-060686 [28]

Answer:

a) their potential energy increases.

Explanation:

Ohm's Law is

R= V/I

Where R= Resistance

V= potential difference or potential energy

I= current or conduction electron flow rate

Clearly R and V are directly proportional i-e Potential energy increases with resistance.

3 0
3 years ago
A helicopter has blades of length 4.0 m rotating at 3.0 rev/s in a horizontal plane.If the vertical component of the Earth’s mag
VARVARA [1.3K]

Answer:

Induced emf, \epsilon=9.79\times 10^7\ volts

Explanation:

Given that,

Length of the helicopter, l = 4 m

Angular speed of the helicopter, \omega=3\ rev/s=18.84\ rad/s

The vertical component of the Earth’s magnetic field is, B=6.5\times 10^5\ T

We need to find the induced emf between the tip of a blade and the hub. The induced emf in terms of angular velocity of an rotating object is given by :

\epsilon=\dfrac{1}{2}B\omega l^2

\epsilon=\dfrac{1}{2}\times 6.5\times 10^5\times 18.84\times (4)^2

\epsilon=9.79\times 10^7\ volts

So, the induced emf between the tip of a blade and the hub is \epsilon=9.79\times 10^7\ volts. Hence, this is the required solution.

5 0
3 years ago
An electron and a proton each have a thermal kinetic energy of 3kBT/2. Calculate the de Broglie wavelength of each particle at a
S_A_V [24]

Answer:

Given:

Thermal Kinetic Energy of an electron, KE_{t} = \frac{3}{2}k_{b}T

k_{b} = 1.38\times 10^{- 23} J/k = Boltzmann's constant

Temperature, T = 1800 K

Solution:

Now, to calculate the de-Broglie wavelength of the electron, \lambda_{e}:

\lambda_{e} = \frac{h}{p_{e}}

\lambda_{e} = \frac{h}{m_{e}{v_{e}}              (1)

where

h = Planck's constant = 6.626\times 10^{- 34}m^{2}kg/s

p_{e} = momentum of an electron

v_{e} = velocity of an electron

m_{e} = 9.1\times 10_{- 31} kg = mass of electon

Now,

Kinetic energy of an electron = thermal kinetic energy

\frac{1}{2}m_{e}v_{e}^{2} = \frac{3}{2}k_{b}T

}v_{e} = \sqrt{2\frac{\frac{3}{2}k_{b}T}{m_{e}}}

}v_{e} = \sqrt{\frac{3\times 1.38\times 10^{- 23}\times 1800}{9.1\times 10_{- 31}}}

v_{e} = 2.86\times 10^{5} m/s                    (2)

Using eqn (2) in (1):

\lambda_{e} = \frac{6.626\times 10^{- 34}}{9.1\times 10_{- 31}\times 2.86\times 10^{5}} = 2.55 nm

Now, to calculate the de-Broglie wavelength of proton, \lambda_{e}:

\lambda_{p} = \frac{h}{p_{p}}

\lambda_{p} = \frac{h}{m_{p}{v_{p}}                             (3)

where

m_{p} = 1.6726\times 10_{- 27} kg = mass of proton

v_{p} = velocity of an proton

Now,

Kinetic energy of a proton = thermal kinetic energy

\frac{1}{2}m_{p}v_{p}^{2} = \frac{3}{2}k_{b}T

}v_{p} = \sqrt{2\frac{\frac{3}{2}k_{b}T}{m_{p}}}

}v_{p} = \sqrt{\frac{3\times 1.38\times 10^{- 23}\times 1800}{1.6726\times 10_{- 27}}}

v_{p} = 6.674\times 10^{3} m/s                               (4)                    

Using eqn (4) in (3):

\lambda_{p} = \frac{6.626\times 10^{- 34}}{1.6726\times 10_{- 27}\times 6.674\times 10^{3}} = 5.94\times 10^{- 11} m = 0.0594 nm

7 0
3 years ago
Other questions:
  • What is the gravitational potential energy of a rock with the mass of 67 kg if it is sitting on top of a hill .35 kilometers hig
    15·1 answer
  • In order to create an electromagnet, you would ?
    6·2 answers
  • If a balloon containing 1,200 L of gas at 25°C and 760 mmHg pressure ascends to an altitude where the pressure is 380 mmHg and t
    12·1 answer
  • Odina walked down the hall at school from the cafeteria to
    8·2 answers
  • PLEASE HELP ME
    5·1 answer
  • What part of the crane is used to lift and lower the load?
    14·2 answers
  • Which of these components is not necessary for current to flow in a series or parallel circuit?
    11·1 answer
  • g You shine orange laser light that has a wavelength of 600 nm through a narrow slit. The slit forms a diffraction pattern on a
    9·1 answer
  • The rate of change in position at a given point in time
    9·1 answer
  • Describe the importance of conservative forces to conservation of energy.
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!