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Oxana [17]
3 years ago
7

Carl runs 100m West. He then runs 60m North. He then runs 20m East. The total distance travelled by Carl is ______m and his tota

l displacement is _____m.
Physics
1 answer:
drek231 [11]3 years ago
4 0

<u>Answer:</u>

   Displacement = 100 meter

   Distance covered = 180 meter.

<u>Explanation:</u>

   Let east represents positive x- axis and north represent positive y - axis. Horizontal component is i and vertical component is j.

  Carl runs 100 m West, Displacement = -100 i

  He then runs 60 m North, Displacement = 60 j

   He then runs 20 m East, Displacement = 20 i

  Total displacement of Carl's running = -100 i + 60 j + 20 i = (-80 i + 60 j) m (Vector)

  Magnitude of displacement =  \sqrt{(-80)^2+60^2} =100 m

  Distance traveled by Carl = 100 + 60 + 20 = 180 m ( Scalar)

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Determine the number of atoms in the following chemical formulas. Make sure you list the elements, how many atoms of each elemen
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Answer:

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Explanation:

Explanation:

In a chemical formula, the symbols for each element in the compound are followed by subscripts that tell us how many of that element are in the compound.

For an example, let's look at the the formula for compound glucose:

C 6  H 12  O 6

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The subscripts that follow each element's symbol indicate how many of that element are in the compound.

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3 years ago
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A 4.4 kg mess kit sliding on a frictionless surface explodes into two 2.2 kg parts, one moving at 2.9 m/s, due north, and the ot
sp2606 [1]

Answer:

Original speed of the mess kit = 4.43 m/s at 50.67° north of east.

Explanation:

Let north represent positive y axis and east represent positive x axis.

Here momentum is conserved.

Let the initial velocity be v.

Initial momentum = 4.4 x v = 4.4v

Velocity of 2.2 kg moving at 2.9 m/s, due north = 2.9 j m/s

Velocity of 2.2 kg moving at 6.8 m/s, 35° north of east = 6.9 ( cos 35i + sin35 j ) = 5.62 i + 3.96 j m/s

Final momentum = 2.2 x 2.9 j + 2.2 x (5.62 i + 3.96 j) = 12.364 i + 15.092 j kgm/s

We have

         Initial momentum = Final momentum

         4.4v = 12.364 i + 15.092 j

         v =2.81 i + 3.43 j

Magnitude

        v=\sqrt{2.81^2+3.43^2}=4.43m/s

Direction

       \theta =tan^{-1}\left ( \frac{3.43}{2.81}\right )=50.67^0

       50.67° north of east.

Original speed of the mess kit = 4.43 m/s at 50.67° north of east.

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3 years ago
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earnstyle [38]

Answer:

Let the second medium be air (n₁=1)

The refractive index n₂ of the medium where first medium is air is found (a)

(a) n₂ = 2

Explanation:

Critical angle can be defined as the angle of incidence that provides the angle of refraction of 90°.

Refractive index of a medium can be defined as a number that describes that how fast a light will travel through that medium.

Critical angle and Refractive index are related by:

\theta_{critical}= sin^{-1}(\frac{n_1}{n_2})

sin \theta_{critical}=\frac{n_1}{n_2}

To find refractive index of medium with respect to air, substitute n₁=1 (Refractive index of air is 1)

Also θ(critical)=30°

Find n₂ :

sin30= \frac{1}{n_2}\\0.5=\frac{1}{n_2}\\n_2=\frac{1}{0.5}\\n_2=2

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3 years ago
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Answer:

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In a double slit experiment, 450 nm light passes through two slits producing an interference pattern where the first bright frin
musickatia [10]

Answer:

1.3 x 10⁻⁴ m

Explanation:

\lambda = wavelength of the light = 450 nm = 450 x 10⁻⁹ m

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d = separation between the slits

For bright fringe, Using the equation

d Sinθ = n \lambda

Inserting the values

d Sin0.2° = (1) (450 x 10⁻⁹)

d (0.003491) = (450 x 10⁻⁹)

d = 1.3 x 10⁻⁴ m

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