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Oxana [17]
3 years ago
7

Carl runs 100m West. He then runs 60m North. He then runs 20m East. The total distance travelled by Carl is ______m and his tota

l displacement is _____m.
Physics
1 answer:
drek231 [11]3 years ago
4 0

<u>Answer:</u>

   Displacement = 100 meter

   Distance covered = 180 meter.

<u>Explanation:</u>

   Let east represents positive x- axis and north represent positive y - axis. Horizontal component is i and vertical component is j.

  Carl runs 100 m West, Displacement = -100 i

  He then runs 60 m North, Displacement = 60 j

   He then runs 20 m East, Displacement = 20 i

  Total displacement of Carl's running = -100 i + 60 j + 20 i = (-80 i + 60 j) m (Vector)

  Magnitude of displacement =  \sqrt{(-80)^2+60^2} =100 m

  Distance traveled by Carl = 100 + 60 + 20 = 180 m ( Scalar)

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12500(kg*m/s)

Explanation:

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A stuntman with a mass of 80.5 kg swings across a moat from a rope that is 11.5 m. At the bottom of the swing the stuntman's spe
goldenfox [79]

Answer:

  • No
  • 5.49 m/s

Explanation:

The net force required to accelerate the stuntman in a circular arc of radius 11.5 m will be ...

  F = mv²/r . . . . where this m is the mass being accelerated, v is the tangential velocity, and r is the radius.

Here, the net force needs to be ...

  F = (80.5 kg)(8.45 m/s)²/(11.5 m) . . . . . where this m is meters

  ≈ 499.8175 kg·m/s² = 499.8 N

Gravity exerts a force on the stuntman of ...

  F = mg = (80.5 kg)(9.8 m/s²) = 788.9 kg·m/s² = 788.9 N

Then the tension required in the rope/vine is ...

  499.8 N+788.9 N= 1288.7 N

This is more than the capacity of the rope, so we do not expect the stuntman to make it across the moat.

_____

The allowed net force for centripetal acceleration is ...

  1000 N -788.9 N = 211.1 N

Then the allowed velocity is ...

  211.1 = 80.5v²/11.5

  30.16 = v² . . . .  multiply by 11.5/80.5

  5.49 = v . . . . . . take the square root

The maximum speed the stuntman can have is 5.49 m/s.

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<em>Comment on crossing the moat</em>

The kinetic energy at the bottom of the swing translates to potential energy at the end of the swing. At the lower speed, the stuntman cannot rise as high, so will traverse a shorter arc. At 8.45 m/s, the moat could be about 16.8 m wide; at 5.49 m/s, it can only be about 11.5 m wide.

5 0
3 years ago
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ziro4ka [17]

Answer:

Radius, r = 0.00523 meters

Explanation:

It is given that,

Magnetic field, B=2\ mT=2.2\times 10^{-3}\ T

Current in the toroid, I = 9.6 A

Number of turns, N = 6

We need to find the radius of the toroid. The magnetic field at the center of the toroid is given by :                  

B=\dfrac{\mu_oNI}{2\pi r}

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Answer:

If this is a multiple choice question, then the answer is D.

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5 0
3 years ago
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