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mezya [45]
3 years ago
6

Consider the unbalanced equation for the combustion of hexane: C6H14 (g) O2 (g) --> CO2 (g) H2O (g) Balance the equation and

determine how many moles of O2 are required to react completely with 7.2 moles of C6H14.
Chemistry
1 answer:
DedPeter [7]3 years ago
6 0

The balanced equation is

2 C6H14 (g) + 19 O2 (g) --> 12 CO2 (g) + 14 H2O (g)

<h3><u>Explanation</u>:</h3>

For solving the stoichiometric calculations, we first need to do two steps. One of them is balancing the reaction equation. Here the balancing is done and we can see that 2 moles of hexane reacts with 19 moles of oxygen to produce 12 moles of carbon dioxide and 14 moles of water.

Now, for 2 moles of hexane, number of moles of oxygen required is 19.

So, for 7.2 moles of hexane, number of moles of oxygen required is\frac {19}{2}\times 7.2.

= 68.4.

So 68.4 moles of oxygen is required.

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A gas occupies 200ml at a temperature of 26 degrees Celsius and 76mmHg pressure. Find the volume at -3degree Celsius with the pr
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184.62 ml

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From the ideal gas equation, pv=mRT

Where p is the pressure, v is the volume, T is the temperature in Kelvin, m is the mass of air in kg, R is the specific gas constant.

For the initial condition,

p_1v_1=mRT_1 \\\\mR= \frac{p_1v_1}{T_1}\cdots(ii)

For the final condition,

p_2v_2=mRT_2 \\\\mR= \frac{p_2v_2}{T_2}\cdots(iii)

Equating equation (i), and (ii)

\frac{p_1v_1}{T_1}=\frac{p_2v_2}{T_2}

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3 years ago
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The balanced equilibrium reaction is,

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The expression of reaction quotient for this reaction is,

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Now put all the given values in this expression, we get

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