Answer:
Explanation:
Let hockey puck is moving at constant speed v
so here we have
so time taken by the puck to strike the wall is given as
now time taken by sound to come back at the position of shooter is given as
so we know that total time is 1.9 s
now we have
Answer:
a = 603.59 m/s^2
Explanation:
from the data given . the rate of change in magnetic field is as follow
from the faraday's law of induction , the expression for the induced emf in region of radius r as follow
electric field at point P_1 as follow
from newton 2nd law of motion, the acceleration of proton is
F = ma
qE = ma
a = 603.59 m/s^2
Answer:
After 12 seconds, the area enclosed by the ripple will be increasing rapidly at the rate of 1206.528 ft²/sec
Explanation:
Area of a circle = πr²
where;
r is the circle radius
Differentiate the area with respect to time.
dr/dt = 4 ft/sec
after 12 seconds, the radius becomes =
To obtain how rapidly is the area enclosed by the ripple increasing after 12 seconds, we calculate dA/dt
dA/dt = 1206.528 ft²/sec
Therefore, after 12 seconds, the area enclosed by the ripple will be increasing rapidly at the rate of 1206.528 ft²/sec