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4 years ago

Example sentence for gravitational potential energy

Physics

1 answer:

andreev551 [17]4 years ago

5 0

Answer:

Explanation:

An object falling loses gravitational potential energy and gains kinetic energy. The gravity potential is the gravitational potential energy per unit mass. This energy comes from the gravitational potential energy released when the water falls. ... At 0, all the energy is in gravitational potential energy.

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So I got a new fit I had to try it on

diamong [38]

Answer:

mmm No this is off of Pinte-rest.

Explanation:

do i need to goo-gle ima-ge this next i think i do

8 0

3 years ago

What is the smallest time interval in which a 5.7 T magnetic field can be turned on or off if the induced emf around the patient

VLD [36.1K]

The smallest time interval in which the magnetic field can be turned on or off to induced the emf is 47.5 s.

<h3>Emf induced in the coil</h3>

The emf induced in the coil is calculated as follows;

emf = dФ/dt

where;

dФ is change in flux
dt is change in time

0.12 = 5.7/dt

dt = 5.7/0.12

dt = 47.5 s

Thus, the smallest time interval in which the magnetic field can be turned on or off to induced the emf is 47.5 s.

Learn more about emf here: brainly.com/question/13744192

#SPJ11

3 0

2 years ago

Consider the following four objects: a hoop, a flat disk, a solid sphere, and a hollow sphere. Each of the objects has mass M an

Mumz [18]

Answer:

The hoop

Explanation:

We need to define the moment of inertia of the different objects, that is,

DISK:

$I_{disk} = \frac{1}{2} mR^2$

HOOP:

$I_{hoop} = mR^2$

SOLID SPHERE:

$I_{ss} = \frac{2}{5}mR^2$

HOLLOW SPHERE

$I_{hs} = \frac{2}{3}mR^2$

If we have the same acceleration for a Torque applied, then

$mR^2>\frac{2}{3}mR^2>\frac{1}{2} mR^2>\frac{2}{5}mR^2$

$I_{hoop}>I_{hs} >I_{disk}>I_{ss}$

The greatest momement of inertia is for the hoop, therefore will require the largest torque to give the same acceleration

4 0

3 years ago

Sheila weighs 60 kg and is riding a bike. Her momentum on the bike is 340 kg • m/s. The bike hits a rock, which stops it complet

Vikki [24]

Answer:

v₂ = 5.7 m/s

Explanation:

We will apply the law of conservation of momentum here:

$Total\ Initial\ Momentum = m_{1}v_{1} + m_{2}v_{2}\\$

where,

Total Initial Momentum = 340 kg.m/s

m₁ = mass of bike

v₁ = final speed of bike = 0 m/s

m₂ = mass of Sheila = 60 kg

v₂ = final speed of Sheila = ?

Therefore,

$340\ kg.m/s = m_{1}(0\ m/s) + (60\ kg)v_{2}\\v_{2} = \frac{340\ kg.m/s}{60\ kg}\\\\$

6 0

3 years ago

How long does it take for a dropped rock to fall from a height of 8 meters

seropon [69]

Answer:

1.28 s

Explanation:

Given:

Δy = 8 m

v₀ = 0 m/s

a = 9.8 m/s²

Find: t

Δy = v₀ t + ½ at²

(8 m) = (0 m/s) t + ½ (9.8 m/s²) t²

t = 1.28 s

5 0

3 years ago