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saul85 [17]
4 years ago
13

What makes the atomic radius change along a period in the periodic table?

Chemistry
1 answer:
Genrish500 [490]4 years ago
7 0

Answer:

D

more protons in the nucleus pull the electrons in, making the atomic radius smaller

Explanation: A p E X !! :)

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Grace injured her ankle while running a relay race at the family reunion. Her aunt breaks the inner, activator portion of an ins
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A

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What can account for the increased potential energy when atoms are close together?
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D. Proton to proton repulsion

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B

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increasing concentration on products will oppose the reaction . the concentration of reactants increase

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Rate of diffusion of hydrogen, compared with the gases of air?
Katarina [22]

Answer:

Graham's law states that the rate of effusion or of diffusion of a gas is inversely proportional to the square root of its molecular weight. So, rate of diffusion of hydrogen gas is four times faster than oxygen gas.

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When the following oxidation-reduction occurs, what is the balanced reduction half-reaction after the electrons in both half rea
Lostsunrise [7]

Answer :  The balanced reduction half-reaction is:

3Cu^{2+}+6e^-\rightarrow 3Cu

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

The given balanced redox reaction is :

Al(s)+Cu^{2+}(aq)\rightarrow Al^{3+}(aq)+Cu(s)

The half oxidation-reduction reactions are:

Oxidation reaction : Al\rightarrow Al^{3+}+3e^-

Reduction reaction : Cu^{2+}+2e^-\rightarrow Cu

In order to balance the electrons, we multiply the oxidation reaction by 2 and reduction reaction by 3 and then added both equation, we get the balanced redox reaction.

Oxidation reaction : 2Al\rightarrow 2Al^{3+}+6e^-

Reduction reaction : 3Cu^{2+}+6e^-\rightarrow 3Cu

The balanced redox reaction will be:

2Al(s)+3Cu^{2+}(aq)\rightarrow 2Al^{3+}(aq)+3Cu(s)

Thus, the balanced reduction half-reaction is:

3Cu^{2+}+6e^-\rightarrow 3Cu

6 0
3 years ago
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