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krek1111 [17]
3 years ago
7

The closest distance a book can be read from a pair of reading eyeglasses (Power = 1.55 dp) is 26.0 cm. What is the near distanc

e?(Assume a distance between the eyeglasses and the eyes to be 3.00 cm)
Physics
1 answer:
Mnenie [13.5K]3 years ago
5 0

Answer:

The image distance is 20.0 cm.

Explanation:

Given that,

Power = 1.55 dp

Distance between book to eye = 26.0+3.00=29.0 cm

We need to calculate the focal length

Using formula of focal length

f = \dfrac{1}{P}

Put the value into the formula

f=\dfrac{1}{1.55}

f=0.645\ m

f=64.5\ cm

We need to calculate the image distance

Using lens formula

\dfrac{1}{f}=\dfrac{1}{u}+\dfrac{1}{v}

\dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{-u}

Put the value into the formula

\dfrac{1}{v}=\dfrac{1}{64.5}-\dfrac{1}{-29}

\dfrac{1}{v}=\dfrac{187}{3741}

v=20.0\ cm

Hence, The image distance is 20.0 cm.

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goblinko [34]

Answer:

4,200 joules per kilogram per degree Celsius

Explanation:

The specific heat capacity of a material is the energy required to raise one kilogram (kg) of the material by one degree Celsius (°C). The specific heat capacity of water is 4,200 joules per kilogram per degree Celsius (J/kg°C). This means that it takes 4,200 J to raise the temperature of 1 kg of water by 1°C.

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2 years ago
How does the agricultural activity most likely affect the surface water of the area?
Radda [10]

Answer:

Agriculture has been the cause of significant modification of landscapes throughout the world. Tillage of land changes the infiltration and runoff characteristics of the land surface, which affects recharge to ground water, delivery of water and sediment to surface-water bodies, and evapotranspiration.

Explanation:

7 0
3 years ago
Read 2 more answers
A four-wheel-drive vehicle is transporting an injured hiker to the hospital from a point that is 30 km from the nearest point on
zepelin [54]

Answer:

D=200\ km

Explanation:

distance on terrain, d_t=30\ km

  • distance on the road, d_r=70\ km
  • speed on terrain, v_t=30\ km.hr^{-1}
  • speed  on road, v_r=130\ km.hr^{-1}

<u>time taken on the terrain,</u>

t_t=\frac{d_t}{v_t}

t_t=\frac{30}{30}

t_t=1\ hr

<u>time taken to cover the distance on the road:</u>

t_r=\frac{d_r}{v_r}

t_r=\frac{70}{130}

t_r=\frac{7}{13}\ hr

<u>Now the distance covered on terrain in the total time:</u>

D= v_r\times (t_r+t_t)

D= 130\times (\frac{7}{13}+1)

D=130\times \frac{20}{13}\

D=200\ km

<em>is the distance the vehicle must target on the road to minimize the time taken in going off the road.</em>

3 0
3 years ago
A child jumps from a moving sled with a speed of 2.2 m/s and in the
butalik [34]

The initial velocity of the sled will be 7.34 m/sec. V is the initial velocity of the sled.

<h3>What is the law of conservation of momentum?</h3>

According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.

The given data in the problem is;

(m₁)  mass of child = 38 kg

(u₁) is the initial velocity child = 2.2 m/s

(m₂) is the mass of sled = 68 kg

(u₂) is the initial velocity of sled = ?

(v) is the velocity after collision = 5.5 m/s

According to the law of conservation of momentum;

Momentum before collision =Momentum after collision

\rm  m_1u_1 + m_2u_2 = v(m_1 + m_2)\\\\(38 \times  2.2) + (68 \times V) = 5.5 \times (38+68) \\\\ 83.6 + 68V = 5.5 \times 106 \\\\  83.6 + 68V =583 \\\\ \rm 68\ V= 583 -83.6 \\\\ \rm 68 \ V= 499.4\\\\ V= 7.34 \ m/sec

Hence,the initial velocity of the sled will be 7.34 m/sec.

To learn more about the law of conservation of momentum refer;

brainly.com/question/1113396

#SPJ1

4 0
2 years ago
The concrete sections of a certain superhighway are designed to have a length of 23.0 m. The sections are poured and cured at 10
loris [4]

Answer:

0.88 cm

Explanation:

Initial length at 10°c, L = 23 m

Rise of temperature, Δt = 42 - 10 = 32°c

Coefficient of linear expansion of concrete, α = 12 x 10^(-6) per°c

Minimum spacing to be left = α L Δt

=12\times10^{-6}\times23\times32

=8.832\times10^{-3}m

= 8.832 x 10^{-1} cm

= 0.88 cm

Note: I have a chosen a general value of 12 x 10^-6 per deg c for coefficient of expansion of  concrete. However, please refer to the value given in your text book and substitute it for an accurate answer.

8 0
3 years ago
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