Speed = 500m/5min = 100 m/min. Direction = west. Velocity = 100 m/min west.
A (b) would be 42 (c) from x to Y mark me as brainlist thanks
Answer:
Melting and frezzing are physical changes
Answer:
Option B is the correct answer.
Explanation:
Let us consider 40 meter above ground as origin.
Initial velocity = 17 m/s
Final velocity = 24 m/s
Acceleration = 9.81 m/s
We have equation of motion v² = u² + 2as
Substituting
24² = 17² + 2 x 9.81 x s
s = 14.63 m
Distance traveled by rock = 14.63 m down.
Height of rock from ground = 40 - 14.63 = 25.37 m = 25.4 m
Option B is the correct answer.
Answer:
3.84 m/s
Explanation:
Using Bernoulli's equation below:
P1 + (1/2ρv1²) + h1ρg = P2 + (1/2ρv2²) + h2ρg
where P1 = P2 atmospheric pressure
(1/2ρv1²) + h1ρg = (1/2ρv2²) + h2pg
collect the like terms
h1ρg - h2ρg = (1/2ρv2²) - (1/2ρv1²)
factorize the expression by removing the like terms on both sides
gρ(h1 - h2) = 1/2ρ( v2² - v1²)
divide both side by rho (density in kg/m³, ρ )
g(h1 - h2) = 1/2 (v2² - v1²)
assuming the surface of the tank is large and the speed of water then at the tank surface v1 = 0
2g(h1 - h2) = v2²
take the square root of both side and h1 - h2 is the difference between the surface of the tank and the opening where water is coming out in meters
√2g(h1 - h2) = √ v2²
v2 = √2g(h1-h2) = √ 2 × 9.81×0.75 = 3.84 m/s
