All categories

4 years ago

What is the name for 3Na2SO4

Chemistry

2 answers:

Strike441 [17]4 years ago

8 0

Answer:

The name for $Na_2SO_4$ is written as: Sodium sulfate

Explanation:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

The nomenclature of ionic compounds is given by:

1. Positive ion is written first.

2. The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'. if the negative ion is polyatomic ion of oxyanion like $SO_4^{2-},NO_3^{-}$ sulfates and nitrates respectively.

The name for $Na_2SO_4$ is written as: Sodium sulfate

Whitepunk [10]4 years ago

4 0

Sodium sulfate is the answer you are looking for

You might be interested in

Can someone help me please ?

zvonat [6]

Answer:

1.w

2. Z

3. Y

4.X

...................

4 0

3 years ago

Where does biomass comes from

tino4ka555 [31]

Biomass is an organic material which has stored sunlight in the from of chemical energy<span> biomass can fuel wood waste, manure, sugarcane, and other byproducts. biomass is a renewable energy source because the energy it comes from is the sun

i hope this helps </span>

7 0

3 years ago

In the chemical laboratory, what does a mortar and pestle function as?. .

Eduardwww [97]

In a chemical laboratory, a mortar and pestle function is to decrease surface area of a solute. The correct answer is B.

3 0

3 years ago

Read 2 more answers

Liquids and gases are matter because they take up space and have

Aneli [31]

Volume. Gases and liquids are typically measured in milliliters (mL) or cubic centimeters (cm^3) - both of which are equivalent (1 mL = 1 cm^3).

8 0

3 years ago

A(g) + 2B(g) → C(g) + D(g)

WITCHER [35]

Answer:

0.169

Explanation:

Let's consider the following reaction.

A(g) + 2B(g) ⇄ C(g) + D(g)

We can find the pressures at equilibrium using an ICE chart.

A(g) + 2 B(g) ⇄ C(g) + D(g)

I 1.00 1.00 0 0

C -x -2x +x +x

E 1.00-x 1.00-2x x x

The pressure at equilibrium of C is 0.211 atm, so x = 0.211.

The pressures at equilibrium are:

pA = 1.00-x = 1.00-0.211 = 0.789 atm

pB = 1.00-2x = 1.00-2(0.211) = 0.578 atm

pC = x = 0.211 atm

pD = x = 0.211 atm

The pressure equilibrium constant (Kp) is:

Kp = pC × pD / pA × pB²

Kp = 0.211 × 0.211 / 0.789 × 0.578²

Kp = 0.169

6 0

3 years ago