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3 years ago

How do you balance S8+F2=SF6

1 answer:

3 0

Balance the followig example of a heterogeneous equilibrium and write its reaction quotient, Qc: S8 + F2=SF6 i've balanced it i think i got S8 +24F2 =8SF6 but when i try it it keeps telling me that i'm wrong when i write out the Qc

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Use mass number in a sentence

luda_lava [24]

Mass number is apart of (what ever subject it is)

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3 years ago

Answer ASAP 25 points

kykrilka [37]

Answer: The correct answer is $NH_3$ is the base and $NH_4Cl$ is the salt.

Explanation:

Neutralization reaction is defined as the reaction in which an acid reacts with a base to produce salt and water as products.

According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and a base is defined as a substance which accepts protons.

For the given chemical reaction:

$NH_3+HCl\rightarrow NH_4Cl$

Here, $NH_3$ is a base because it is accepting proton and HCl is an acid because it is loosing proton.

$NH_4Cl$ is considered as a salt because it is formed by the combination of acid and base.

Hence, the correct answer is $NH_3$ is the base and $NH_4Cl$ is the salt.

8 0

3 years ago

Read 2 more answers

You complete a chemical reaction and recover 79 grams of product. However, you calculate you should have recovered 104 grams of

spin [16.1K]

Percent yield is calculated using:
$percent \: yield = \frac{actual \: yield}{theoretical \: yield} \times 100\%$

Your actual yield is how much you actually had at the end of the experiment = 79g.

Your theoretical yield is how much you calculated you should have gotten in an ideal, perfect experiment = 104g.

So put those values into the equation:
$percent \: yield = \frac{79}{104} \times 100\% = 76\%$

5 0

4 years ago

Calculate the concentration (M) of sodium ions in a solution made by diluting 50.0 mL of a 0.874 M solution of sodium sulfide to

statuscvo [17]

Answer:

Since one mole Na₂S ionised to give 2moles Na⁺ ion, hence concentration of sodium ion in the solution is (2 × 0.1748)M = 0.3496 M

≈0.350 M

Explanation:

From the question it is clear that,

Initial volume of sodium sulphide solution is (v₁) = 50mL

Initial concentration of sodium sulphide solution is (s₁) =0.874 M

Final volume of sodium sulphide solution is (v₂) = 250mL

Let, the final concentration of sodium sulphide solution is s₂, then according to acidimetry-alkalimetry,

v₁ × s₁ = v₂ × s₂

Or, s₂ = v₁ × s₁/v₂

= 50 × 0.874 / 250

= 0.1748 M

Therefore, concentration of 250mL sodium sulphide solution is 0.1748 M

Since one mole Na₂S ionised to give 2moles Na⁺ ion, hence concentration of sodium ion in the solution is (2 × 0.1748)M = 0.3496 M

≈0.350 M

5 0

3 years ago

Why is the following equation invalid? Al + 202 → Al2O3

Ket [755]

Answer:

C. The equation violates the Law of Conservation of Mass

Explanation:

This equation is invalid because it violated the Law of conservation of Mass. The correct option is C.

This law establishes that the mass is not preserved or destroyed, but transformed.

That is why in a chemical reaction, the number of atoms involved in the reagents and products must be equal.

to achieve this it is necessary to perform a reaction adjustment.

The correct equation would be:

$2Al + 3O_{2}$ ⇄ $2Al_{2} O_{3}$

7 0

3 years ago

Read 2 more answers