<span>0.38
You first calculate the total moles by dividing the grams by molecular weight:
45 g N2 / 28.02 g/mol = 1.6 mol N2
40 g Ar / 39.95 g/mol = 1.0 mol
Then you divide the moles of Ar by the total number of moles:
1.0 / (1.6 + 1.0) = 0.38 mol fraction</span>
Answer:
Reactants, Activation energy, Energy released by the reaction and Products
Explanation:
This energy profile is that of an exothermic reaction. In an exothermic reaction, heat is liberated to the surrounding. The surrounding becomes hotter than the environment.
The first box to the left is the reactants which signifies the species combining together.
The topmost box is the activation energy which is the energy barrier that must be over come before a reaction takes place.
The box underneath is the energy change. Here, energy is being released.
The right most box is the product of the reaction.
Answer:
The solubility product of zinc sulfide is
.
Explanation:
Solubility of the zinc sulfide = 

S S
The expression of solubility product is given by :
![K_{sp}=[Zn^{2+}]\times [S^{2-}]](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BZn%5E%7B2%2B%7D%5D%5Ctimes%20%5BS%5E%7B2-%7D%5D)


The solubility product of zinc sulfide is
.
Answer: 2.0 moles of oxygen are needed to completely react with 1.0 mole of CH4 as shown in the balanced equation.
Explanation:
Stoichiometry is a fundamental tool and skill to determine the relative quantities that the chemicals react with. it determines the quantity of one substance to a quantity of another substance or substances. Stoichiometry is relating of one chemical substance to another using a balanced chemical reaction is called stoichiometry. Also, it is very important to predict what will occur and how much is produced through knowing the coefficients of moles of reactants and products.
Mole s defined as the mass of the substance divided by its molar mass.
As shown from the balanced equation every mole of methane(CH4) needs to react with 2.0 moles of oxygen(O2) to produce 1.0 mole of carbon dioxide(CO2) and 2.0 moles of hydrogen peroxide(H2O2).