Which organ system directs the other organ systems in our bodies?

A chemistry student is given 700. mL of a clear aqueous solution at 26.Â° C. He is told an unknown amount of a certain compound

Alex73 [517]

Answer:

The correct answer is - yes, 4.57 g of solute per 100 ml of solution

Explanation:

The correct answer is yes we can calculate the solubility of X in the water at 22.0Â°C. The salt will remain after the evaporate from the dissolved and cooled down at 26Â°C.

Then, the amount of solute dissolved in the 700 ml solution at 26°C is the weighed precipitate: 0.032 kg = 32 g.

Then solublity will be :

32. g solute / 700 ml solution = y / 100 ml solution

⇒ y = 32. g solute × 100 ml solution / 700 ml solution = 4.57 g.

Thus, the answer is 4.57 g of solute per 100 ml of solution.

5 0

2 years ago

Enter the appropriate symbol for an isotope of calcium-42 corresponding to the isotope notation AZX

Sergio [31]

40 20Ca this is the appropriate symbol for an isotope of calcium-42 corresponding to the isotope notation AZX

3 0

3 years ago

Read 2 more answers

What is the balanced form of the following equation? Br 2 + S 2 O 3 2– + H 2 O → Br 1– + SO 4 2– + H +

nikitadnepr [17]

Answer:

4Br₂+ 5H₂O+ S₂O₃²⁻ → 2SO₄²⁻ + 10H⁺ + 8Br⁻

Explanation:

Br₂ + S₂O₃²⁻ + H₂O → Br⁻ + SO₄²⁻ + H⁺

This is a redox reaction:

Br₂ changes the oxidation state from 0 to -1, so it was reduced

In the S₂O₃⁻² anion S changes the oxidation state from +2 to +6 in sulfate anion. (S₂O₃⁻², it is called thiosulfate)

We have protons in the main equation, so we assume we are in acidic medium:

Br₂ + 2e⁻ → 2Br⁻ Reduction

We balanced the bromide with 2, so the bromine has gained 2 electrons.

5H₂O + S₂O₃²⁻ → 2SO₄²⁻ + 10H⁺ + 8e- Oxidation

First of all, we add 2 to the sulfate anion in the product side, in order to balance the S.

As we have 8 O in right side, and 3 O in left side, we must add 5 O. We add 5 water in the place where the O are lower (reactant side).

Now, we have 10 H, in the reactant side, so we balance the product side with protons (10 H⁺).

Sulfur changed the oxidation state from +2 to +6, so it released 4 electrons, but, if you see thiosulfate anion you have 2 sulfurs so finally it has released 8 electrons.

Electrons are unbalanced so we multiply reduction x4, and oxidation x1.

(Br₂ + 2e⁻ → 2Br⁻) . 4 = 4Br₂ + 8e⁻ → 8Br⁻

(5H₂O + S₂O₃²⁻ → 2SO₄²⁻ + 10H⁺ + 8e-) . 1 = STAYS THE SAME.

We sum both half reactions, to cancel the elecetrons:

4Br₂ + 8e⁻ + 5H₂O + S₂O₃²⁻ → 2SO₄²⁻ + 10H⁺ + 8e- + 8Br⁻

Finally the balanced reaction is: 4Br₂+ 5H₂O+ S₂O₃²⁻ → 2SO₄²⁻ + 10H⁺ + 8Br⁻

5 0

3 years ago

What happens when energy is released during atomic fission

Vesnalui [34]

Nuclear energy is called the energy obtained by the transformation of atomic nuclei, so small and heavy clusters of particles inside the atom. Nuclear energy can be produced in two ways, by cleavage or synthesis of nuclei. Heavy nuclei of radioactive elements such as uranium or plutonium, can be split into two nuclei. By splitting are released from the nucleus of neutrons that collide with other nuclei causing them to split and subsequent emission of neutrons. This is called a chain reaction. The condition calls self-sustaining nuclear reaction is slowing down neutrons. For this purpose, a special substance, called moderator. The neutrons collide with the molecules of the moderator precipitate heating speed while the moderator. The resulting heat heats the water so that a couple who drives a turbine generating electricity. Another way of producing nuclear energy is nuclear fusion, in which nuclei combine to light elements. So far, fusion, however, failed to carry out so that it can be applied to the economy as a source of energy.

4 0

3 years ago

A precipitate of lead(II) chromate can be formed using the reaction below.

Marina86 [1]

Answer:

hi

Explanation:

7 0

3 years ago