Answer:
Your question seems to me that it is somewhat poorly written, but it could help you by telling you that by increasing the collision of the individuals, the friction between them increases, therefore increasing the release of energy in the form of heat and thus increasing the temperature.
Therefore, the hypothesis raised would be correct.
Explanation:
If the shock is perfectly inelastic (plastic), the kinetic energy is not conserved and, as a consequence, the colliding bodies can undergo deformations and increase in temperature.
Answer is: the identity of the isotope is silver (Ag-107).
p⁺(isotope) = 47; number of protons in isotope.
Z = p⁺; atomic number.
Atomic number is the number of protons, which is characteristic of a chemical element, silver is an element with atomic number 47.
n°(isotope) = 60; number of neutrons in isotope.
A = p⁺ + n°; mass number is the total number of protons and neutrons in a nucleus.
A = 47 + 60.
A = 107.
Answer:
FALSE
Explanation:
Br is <em>bromine</em> with atomic number 35, mass number of 79.904 and belongs to the group 7 elements known as the halogens.
Ga is <em>gallium</em> with atomic number 31, mass number of 69.72 and belongs to the alkaline earth metal i.e the group 3 elements.
From the above and in terms of their mass number, it is evident that Br is the larger element compared to Ga which is lesser than Br. Hence the statement is FALSE
Answer:
As the amount of substances increases density will increase.
Explanation:
Density and mass have direct relation while density and volume has inverse relation. If the volume of substance is kept constant then the density of substance will increase with same factor as the mass of substance is increases.
Density:
Density is equal to the mass of substance divided by its volume.
Units:
SI unit of density is Kg/m3.
Other units are given below,
g/cm3, g/mL , kg/L
Formula:
D=m/v
D= density
m=mass
V=volume
Symbol:
The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.
Answer
Explanation
We need a conversion factor that will converts from moles of glucose, C6H12O6 to molecules of glucose.
That is, one mole of any substance contains 6.022 x 10²³ molecule of that substance.
1.5055 x 10^24 molecules of glucose are in 2.5 moles of glucose C6H12O6
