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emmasim [6.3K]
2 years ago
11

If a solution contains 20g of glycerol and 5g of coeine, what is the codeine percentage strength of the solution?

Chemistry
1 answer:
Strike441 [17]2 years ago
5 0

20%

The codeine percentage strength of the solution is 20%

  • The term "percent strength" describes the proportion of a material that has dissolved in a given volume of liquid.
  • Knowing how parts relate to wholes is the secret of % strength: A percent is equal to x parts out of 100 overall.

<h3>Meaning of percentage strength</h3>
  • The amount of a liquid is often measured, and the % strength tells you how many parts by volume of the active ingredient are present.
  • 100 parts by volume are included in the total volume of the solution or liquid preparation.

<h3>How do you determine a solution's strength?</h3>

Mass of solute times strength of solution(g) Amount of the solution(L)

  • The amount of solute dissolved in grams per liter of the solution is used to determine the solution's strength.
  • It stands for the solution's potency or concentration.
  • It uses grams per liter to express.

To learn more about percentage strength visit:

brainly.com/question/14661341

#SPJ4

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C2H4O2 + NaC2H3O2 + H2O + CO2 list the reactants in this chemical reaction
lisabon 2012 [21]

Answer:

C₂H₄O₂ and NaC₂H₃O₂ are reactants.

Explanation:

Word equation:

Acetic acid + sodium acetate  → sodium diacetate

Chemical equation:

C₂H₄O₂ + NaC₂H₃O₂  →  C₄H₇NaO₄

This is a synthesis reaction in which simple reactants combine to form complex product.

This is also balanced chemical equation because there are equal number of atoms of all elements on both side of equation. Thus it follow the law of conservation of mass.

Law of conservation of mass:

According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.

This law was given by french chemist  Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.

7 0
3 years ago
The conversion of acetyl chloride to methyl acetate occurs via the following two-step mechanism: Reaction sequence of acetyl chl
Svetlanka [38]

If the concentration of acetyl chloride  is increased ten times the rate of reaction is increased ten times.

The conversion of acetyl chloride to methyl acetate is a substitution reaction. Recall that a substitution reaction is one in which a moiety in a molecule is replaced by another.

In this reaction, the CH3O- ion replaces the chloride ion. In the first step, the CH3O- ion attacks the substrate in a slow step. This creates a tetrahedral intermediate. Loss of the chloride ion yields the  methyl acetate product.

The rate determining step is the formation of the tetrahedral intermediate. Since the reaction is first order in the acetyl chloride, if its concentration is increased ten times the rate of reaction is increased ten times.

Learn more: brainly.com/question/5624100

4 0
2 years ago
B- How many electrons does sodium have?
ziro4ka [17]

Answer: sorry I’m late but it is 11 electrons

Explanation:

7 0
3 years ago
If you have 5 moles of carbon dioxide at 30degrees C and under 600mmHg of pressure, what will the volume be
trapecia [35]

Answer:

157.64 L

Explanation:

We'll begin by converting 30 °C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

T(°C) = 30 °C

T(K) = 30 °C + 273

T (K) = 303 K

Next, we shall convert 600 mmHg to atm. This can be obtained as follow:

760 mmHg = 1 atm

Therefore,

600 mmHg = 600 mmHg × 1 atm / 760 mmHg

600 mmHg = 0.789 atm

Finally, we shall determine the volume of the gas. This can be obtained as follow:

Number of mole (n) = 5 moles

Temperature (T) = 303 K

Pressure (P) = 0.789 atm

Gas constant (R) = 0.0821 atm.L/Kmol

Volume (V) =?

PV = nRT

0.789 × V = 5 × 0.0821 × 303

0.789 × V = 124.3815

Divide both side by 0.789

V = 124.3815 / 0.789

V = 157.64 L

Therefore, the volume of the gas is 157.64 L

7 0
2 years ago
What might law enforcement do to reduce attempts at deception when gaining a handwriting sample?
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In order to decrease the chances of deception in acquiring a handwriting sample, what the law enforcement do is that, they ask they person to write as little as possible, write the passage only once and also gather the material that consist some of the similar words and phrases as the suspected document. Answer for this would be all of the above.
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3 years ago
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