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emmasim [6.3K]
2 years ago
11

If a solution contains 20g of glycerol and 5g of coeine, what is the codeine percentage strength of the solution?

Chemistry
1 answer:
Strike441 [17]2 years ago
5 0

20%

The codeine percentage strength of the solution is 20%

  • The term "percent strength" describes the proportion of a material that has dissolved in a given volume of liquid.
  • Knowing how parts relate to wholes is the secret of % strength: A percent is equal to x parts out of 100 overall.

<h3>Meaning of percentage strength</h3>
  • The amount of a liquid is often measured, and the % strength tells you how many parts by volume of the active ingredient are present.
  • 100 parts by volume are included in the total volume of the solution or liquid preparation.

<h3>How do you determine a solution's strength?</h3>

Mass of solute times strength of solution(g) Amount of the solution(L)

  • The amount of solute dissolved in grams per liter of the solution is used to determine the solution's strength.
  • It stands for the solution's potency or concentration.
  • It uses grams per liter to express.

To learn more about percentage strength visit:

brainly.com/question/14661341

#SPJ4

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Answer:

The answer is

<h2>1040g</h2>

Explanation:

Density = mass / volume

mass = density × volume

volume = 2cm³

density = 520g/cm³

mass = 2 × 520

= 1040g

Hope this helps you

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3 years ago
What could two atoms of the same element form?
scZoUnD [109]
Covalent bonds but not ionic 
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What is the potential energy of the reactants from the following energy diagram?
slavikrds [6]
The potential energy of the reactants is 200J.
From the energy diagram, the energy of the product formed is 350J; this means that, this reaction is an endothermic reaction, because it absorbs energy from its environment.<span />
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3 years ago
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At 311 K, this reaction has a K c value of 0.0111 . X ( g ) + 2 Y ( g ) − ⇀ ↽ − 2 Z ( g ) Calculate K p at 311 K. Note that the
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Answer:

K_{p}=4.35\times 10^{-4}

Explanation:

We know, K_{p}=K_{c}(RT)^{\Delta n}

where, R = 0.0821 L.atm/(mol.K), T is temperature in kelvin and \Delta n is difference in sum of stoichiometric coefficient of products and reactants

Here \Delta n=(2)-(2+1)=-1 and T = 311 K

So, K_{p}=(0.0111)\times [(0.0821L.atm.mol^{-1}.K^{-1})\times 311K]^{-1}=4.35\times 10^{-4}

Hence value of equilibrium constant in terms of partial pressure (K_{p}) is 4.35\times 10^{-4}

4 0
3 years ago
Copper, a metal known since ancient times, exists in two stable isotopic forms, 6329Cu (69.09%) and 6529Cu (30.91%). Their atomi
Svetradugi [14.3K]

Answer:

Wt. Avg. Atomic Weight => 63.35457 amu

Explanation:

Given              Isotopic             %Abundance     fractional          Wt Avg

                  At. Mass (amu)                                  abundance      contribution                    

Cu-63              62.93                      69.09              0.6909            43.4783

Cu-65              64.9278                  20.0668        0.200668        20.0668

Wt Average of all isotopes = ∑Wt Avg Contributions

=  43.4783 amu + 20.0668 amu = 63.35457 amu

7 0
3 years ago
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