1. Iron fillings are magnetic, so use a magnet to pull the iron fillings out of the mix.
2. Then you can put the salt and sand mixture into water, since salt is soluble, and the salt will dissolve, leaving you with sand.
Answer:
Below is the clarification of that same particular question.
Explanation:
- Le Chatlier's theory states that whenever an equilibrium mechanism is disrupted by environmental influences, the program responds by changing the supplies information of its constituents in a somewhat way that the disturbance is invalidated and reaches a stable equilibrium during that disrupted stage, with concentrations of stability differently than ever before.
- Bromothymol blue seems to be a phenolic subs lone which always allows it to act throughout aqueous solutions as an acidic solution. Being such an acid (weak), it should not add to rapid, as well as introduces a balance with its accompanying but mostly disconnected form.
<u>For that kind of weak diprotic predictor, the standard economic statement can indeed be published as:</u>
⇒ 
- It could be conclusively proven from either the theory of Le Charlier whereby, that whenever a strong acid becomes applied, the full disorientation of one or the other, through equilibrium formation, induces an increase throughout the medium's proton concentrations.
- Likewise, it absorbs the protons throughout the media to split water that whenever a solution is added. So, particle concentration throughout the medium is decreasing. To accommodate for this transition, the equilibrium reacts by moving to the correct i.e. causing further dissociation of the optimistic predictor into their dianion through protons, thereby attempting to nullify that perturbation.
Answer:
23430.4 J.
Explanation:
From the question given above, the following data were obtained:
Mass (M) = 70 g
Initial temperature (T₁) = 10 °C
Final temperature (T₂) = 90 °C
Specific heat capacity (C) = 4.184 J/gºC
Heat (Q) required =?
Next, we shall determine the change in the temperature of water. This can be obtained as follow:
Initial temperature (T₁) = 10 °C
Final temperature (T₂) = 90 °C
Change in temperature (ΔT) =?
ΔT = T₂ – T₁
ΔT = 90 – 10
ΔT = 80 °C
Finally, we shall determine the heat energy required to heat up the water. This can be obtained as follow:
Mass (M) = 70 g
Change in temperature (ΔT) = 80 °C
Specific heat capacity (C) = 4.184 J/gºC
Heat (Q) required =?
Q = MCΔT
Q = 70 × 4.184 × 80
Q = 23430.4 J
Therefore, 23430.4 J of heat energy is required to heat up the water.
Answer:
4.4 g
Explanation:
Step 1: Write the balanced equation
Cu + 4 HNO₃ ⇒ Cu(NO₃)₂ + 2 NO₂ + 2 H₂O
Step 2: Calculate the moles corresponding to 3.2 L of NO₂ at STP
At standard temperature and pressure, 1 mole of NO₂ occupies 22.4 L.
3.2 L × 1 mol/22.4 L = 0.14 mol
Step 3: Calculate the moles of Cu needed to produce 0.14 moles of NO₂
The molar ratio of Cu to NO₂ is 1:2. The moles of Cu needed are 1/2 × 0.14 mol = 0.070 mol.
Step 4: Calculate the mass corresponding to 0.070 moles of Cu
The molar mass of Cu is 63.55 g/mol.
0.070 mol × 63.55 g/mol = 4.4 g
This is false, they have intermediate properties between suspension and true solution