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Leni [432]
4 years ago
14

Why did you have to remove co2 from your partially neutralized stomach acid before the titration?

Chemistry
1 answer:
shutvik [7]4 years ago
8 0

Answer is: carbon dioxide (CO₂) can affect the end point of the titration.

Carbon dioxide, or carbon(IV) oxide, reacts with water and form carbonic acid, which can affect the end point of the titration, because more base is needed for neutralization of partially neutralized stomach acid.

Balanced chemical reaction of carbon dioxide and water: CO₂ + H₂O → H₂CO₃.

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Devise a way to separate a mixture of sand, salt, and iron filings. Write the procedure using a step-by-step method and explain
aev [14]
1. Iron fillings are magnetic, so use a magnet to pull the iron fillings out of the mix.
2. Then you can put the salt and sand mixture into water, since salt is soluble, and the salt will dissolve, leaving you with sand.
3 0
3 years ago
PLEASE HELP!! What direction do you predict the addition of a base to the solution containing bromophenol blue will drive the eq
marishachu [46]

Answer:

Below is the clarification of that same particular question.

Explanation:

  • Le Chatlier's theory states that whenever an equilibrium mechanism is disrupted by environmental influences, the program responds by changing the supplies information of its constituents in a somewhat way that the disturbance is invalidated and reaches a stable equilibrium during that disrupted stage, with concentrations of stability differently than ever before.
  • Bromothymol blue seems to be a phenolic subs lone which always allows it to act throughout aqueous solutions as an acidic solution. Being such an acid (weak), it should not add to rapid, as well as introduces a balance with its accompanying but mostly disconnected form.

<u>For that kind of weak diprotic predictor, the standard economic statement can indeed be published as:</u>

    ⇒  H_2In_(aq)\rightleftharpoons In^{2-} +2H^+

  • It could be conclusively proven from either the theory of Le Charlier whereby, that whenever a strong acid becomes applied, the full disorientation of one or the other, through equilibrium formation, induces an increase throughout the medium's proton concentrations.
  • Likewise, it absorbs the protons throughout the media to split water that whenever a solution is added. So, particle concentration throughout the medium is decreasing. To accommodate for this transition, the equilibrium reacts by moving to the correct i.e. causing further dissociation of the optimistic predictor into their dianion through protons, thereby attempting to nullify that perturbation.
4 0
3 years ago
A bowl containing 70 grams of water, is heated from 10 °C to 90 °C. The specific heat of
storchak [24]

Answer:

23430.4 J.

Explanation:

From the question given above, the following data were obtained:

Mass (M) = 70 g

Initial temperature (T₁) = 10 °C

Final temperature (T₂) = 90 °C

Specific heat capacity (C) = 4.184 J/gºC

Heat (Q) required =?

Next, we shall determine the change in the temperature of water. This can be obtained as follow:

Initial temperature (T₁) = 10 °C

Final temperature (T₂) = 90 °C

Change in temperature (ΔT) =?

ΔT = T₂ – T₁

ΔT = 90 – 10

ΔT = 80 °C

Finally, we shall determine the heat energy required to heat up the water. This can be obtained as follow:

Mass (M) = 70 g

Change in temperature (ΔT) = 80 °C

Specific heat capacity (C) = 4.184 J/gºC

Heat (Q) required =?

Q = MCΔT

Q = 70 × 4.184 × 80

Q = 23430.4 J

Therefore, 23430.4 J of heat energy is required to heat up the water.

4 0
3 years ago
Please help, and if you could also give me a step by step that would be awesome!!
const2013 [10]

Answer:

4.4 g

Explanation:

Step 1: Write the balanced equation

Cu + 4 HNO₃ ⇒ Cu(NO₃)₂ + 2 NO₂ + 2 H₂O

Step 2: Calculate the moles corresponding to 3.2 L of NO₂ at STP

At standard temperature and pressure, 1 mole of NO₂ occupies 22.4 L.

3.2 L × 1 mol/22.4 L = 0.14 mol

Step 3: Calculate the moles of Cu needed to produce 0.14 moles of NO₂

The molar ratio of Cu to NO₂ is 1:2. The moles of Cu needed are 1/2 × 0.14 mol = 0.070 mol.

Step 4: Calculate the mass corresponding to 0.070 moles of Cu

The molar mass of Cu is 63.55 g/mol.

0.070 mol × 63.55 g/mol = 4.4 g

5 0
3 years ago
Colloids are true solutions. <br><br><br> ____ True ____ False
Reptile [31]
This is false, they have intermediate properties between suspension and true solution
7 0
4 years ago
Read 2 more answers
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