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Illusion [34]
3 years ago
10

3.618X 10^24 molecules of sodium hydroxide (NaOH) would also be ____ grams of NaOH

Chemistry
1 answer:
d1i1m1o1n [39]3 years ago
4 0

Answer:

Mass = 240 g

Explanation:

Given data:

Number of molecules of NaOH = 3.618 × 10²⁴ molecules

Mass in grams = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

For NaOH:

1 mole = 6.022 × 10²³ molecules

3.618 × 10²⁴ molecules × 1 mol /  6.022 × 10²³ molecules

0.6 × 10¹ moles

6 moles

Mass of NaOH:

Mass = Number of moles × molar mass

Mass = 6 mol × 40 g/mol

Mass = 240 g

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Given that the initial rate constant is 0.0110s−1 at an initial temperature of 21 ∘C , what would the rate constant be at a temp
gulaghasi [49]

The rate constant is mathematically given as

K2=2.67sec^{-1}

<h3>What is the Arrhenius equation?</h3>

The rate constant for a particular reaction may be calculated with the use of the Arrhenius equation. This constant can be stated in terms of two distinct temperatures, T1 and T2, as follows:

ln(\frac{K2}{K1})= (\frac{Ea}{R})*(\frac{1}{T1}-\frac{1}{T2})

Therefore

KT1= 0.0110^{-1}

T1= 21+273.15

T1= 294.15K

T2= 200  

T2=200+273.15

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Ea= 35.5 Kj/Mol

Hence, in  j/mol R Ea is

Ea=35.5*1000 j/mol R

ln(\frac{K2}{0.0110})= (\frac{35.5*1000}{8.314})*(\frac{1}{294.15}-\frac{1}{473.15}\\\\ln(\frac{K2}{0.0110})=5.492

K2/0.0110 =e^(5.492)

K2/0.0110 =242.74

K2= 242.74*0.0110

K2=2.67sec^{-1}

In conclusion, rate constant

K2=2.67sec^{-1}

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Explanation:

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The electron configuration of  V³⁺ is [Ar]3d^2. The ion is paramagnetic because it has two unpaired electrons

<h3>What is paramagnetic?</h3>
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  • Diamagnetic materials, in contrast, are attracted to magnetic fields and produce induced magnetic fields that are directed in the opposite direction from the applied magnetic field.
  • The majority of chemical elements and some compounds are considered to be paramagnetic materials.
  • Paramagnetic materials have a relative magnetic permeability that is somewhat more than 1, which makes them attracted to magnetic fields.
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  • Modern experiments on paramagnetic materials are frequently done with a sensitive analytical balance since it typically requires a sensitive analytical balance to identify the effect.

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