Answer:
Step-by-step explanation:
Perimeter of quarter circle = r + r + 
2) d = 2*10 = 20 cm
Perimeter of semicircle = diameter + (1/2) * circumference of circle
3) Perimeter of three-quarter = r + r + (3/4)* circumference of circle
Answer:
Domain- Interval Notation:
(
−
∞
,
∞
)
Set-Builder Notation:
{
x
|
x
∈
R
}
Range- Interval Notation:
(
−
9
,
∞
)
Set-Builder Notation:
{
y
|
y
>
−
9
}
Step-by-step explanation:
Horizontal asymptote- y=-9
Answer:
65.56°
Step-by-step explanation:
= We solve the above question using the Trigonometric function of Tangent
tan θ = Opposite/Adjacent
Opposite = 220 feet = Height of the building
Adjacent = 100 feet = Length of the shadow
Hence,
tan θ = 220/100
tan θ = 2.2
= arctan(2.2)
= 65.55604522°
Approximately = 65.56°
Answer:
5/7
Step-by-step explanation:
6/7-1/7=5/7
Answer:
8.025
Step-by-step explanation:
If you count the zeros in 1000, it's three. Count three starting from the back of 25. Add 0 in front of 25 to make it a three digit number. You then put the decimal point with the whole number.
