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notka56 [123]
3 years ago
13

How can math tools help you detect errors or inaccuracies in data?

Chemistry
1 answer:
elena-14-01-66 [18.8K]3 years ago
4 0
There are a lot of math tools that can be used to detect inaccuracies of data. Math tools usually used to collect, to organize, to analyse and to present data. Math tools are also used to estimate and find the accurate, precise and signification answers to every study. With Math tools, it is easy to detect if there is inaccurate data, like for example measuring the liquid substances, it needs measuring cup to check if the substance you put is precise.



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A chemical equation is balanced by changing or adding
tresset_1 [31]
<span>A chemical equation is balanced by changing or adding C. numbers in front of molecules, which are called coefficients. 
For example:
O2 + 2 H2 ---> 2 H2O (number 2 is added to both sides in order to balance the equation)</span>
6 0
3 years ago
Is green ink homogeneous or heterogeneous?
Leno4ka [110]
<span>Green ink is homogeneous.
please mark as brainliest

</span>
7 0
3 years ago
The radii of the lithium and magnesium ions are 76 pm and 72 pm, respectively. which compound has stronger ionic attraction, lit
quester [9]
 <span>From the Born–Landé equation the lattice energy U ∝ (Z+ × Z-) / (r+ + r-) where Z+ and Z- are the charges on the cation and anion, respectively; r+ and r- are radii of the cation and anion, respectively.

The Z+×Z- term dominates. MgO has 2×2 (4) so it will have the higher U than Li2O Z+ × Z- = 2.
You only consider (r+ + r-) term when the Z+×Z- term is the same; smallest the (r+ + r-),  the larger is the U. 
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<span>U(Li2O) = 2799 kJ mol^-1 

MgO has larger.

</span>
6 0
3 years ago
The solubility of acetanilide is 12.8 g in 100 mL of ethanol at 0 ∘C, and 46.4 g in 100 mL of ethanol at 60 ∘C. What is the maxi
weqwewe [10]

Answer: 72.41% and 26.90% respectively.

Explanation:

At 60°C, you can dissolve 46.4g of acetanilide in 100mL of ethanol. If you lower the temperature, at 0°C, you can dissolve just 12.8g, which means (46.4g-12.8g)=33.6g of acetanilide must have precipitated from the solution.

We can calculate recovery as:

\%R=\frac{crystalized\ mass}{initial\ mass}*100 =\frac{33.6\ g}{46.4\ g}*100=72.41\%

So the answer to the first question is 72.41%.

For the second part just use the same formula, the mass of the precipitate is the final mass minus the initial mass, (171mg-125mg)=46mg.

\%R=\frac{crystalized\ mass}{initial\ mass}*100 =\frac{46\ mg}{171\ mg}*100=26.90\%

So the answer to the second question is 26.90%.

3 0
3 years ago
Write the quantities 3 x 10^-4 cm and 3 x 10^4 km in ordinary notation
Goshia [24]
To write quantities in ordinary notation, you need to notice the power of the exponent.
If the power is positive, then you move the decimal point to the right by the number the power in exponent tells you.
If the power is negative, then you move the decimal point to the left by the number the power in exponent tells you.

We have:
3 x 10^-4 : the power of exponent is negative, therefore, we will move the decimal point 4 places to the left.
3 x 10^-4 = 0.0003 km

3 x 10^4 : he power of exponent is positive, therefore, we will move the decimal point 4 places to the right.
3 x 10^4 = 30000 km
6 0
4 years ago
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