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kirza4 [7]
3 years ago
10

Which option names two processes that must occur to form soil? weathering breaks rocks into minerals and plants die and decay er

osion transports mineral particles and plants die and decay plants produce loam and plants produce humus erosion and weathering
Chemistry
2 answers:
jeka57 [31]3 years ago
8 0

<u>Answer</u>:

"weathering breaks rocks into minerals and plants die and decay"  must occur to form soil

<u>Explanation</u>:

For the formation of the soil two process are mandatory and they are erosion as well as weathering. The weathering takes place near the surface of the soil, which can occur due to various physical and chemical processes. Being an important part of soil development. It may occur rapidly or can be a slow process for decades. Water and air helps in weathering. The transport is generally by wind or with the help of flow of water, ice, etc .,

kodGreya [7K]3 years ago
6 0

Answer: Its B

Explanation:

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Products or solutions found at home or in store and their characteristics
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3 years ago
Suppose 11.4g of ammonium chloride is dissolved in 250 ml of a 0.3M aqueous solution of potassium carbonate. Calculate the final
Sindrei [870]

Answer:

The molarity of the final ammonium cation is 0.252M

Explanation:

<u>Step 1:</u> Data given

Mass of ammonium chloride (NH4Cl) = 11.4 grams

Volume of 0.3 M aqueous solution of potassium carbonate (K2CO3) = 250 mL = 0.250L

<u>Step 2:</u> The balanced equation

2NH4Cl + K2CO3 → 2KCl + (NH4)2CO3

<u>Step 3:</u> Calculate moles of (NH4)Cl

moles (NH4)Cl = 11.4 grams /53.49 g/mol

Moles (NH4)Cl = 0.213 moles

<u>Step 4: </u>Calculate moles of K2CO3

Moles K2CO3 = Molarity * Volume

Moles K2CO3 = 0.3M * 0.250 L = 0.075 moles

<u>Step 5:</u> Calculate moles (NH4)Cl at the equilibrium

For 2 moles (NH4)Cl consumed, we need 1 mole of K2CO3 to produce 2 KCl and 1 mole of (NH4)2CO3

(NH4)2CO3l will dissolve in 2NH4+ + CO32-

Moles (NH4)2Cl = 0.213 moles - 2*0.075 = 0.063 moles

Moles NH4+ = moles (NH4)Cl = 0.063 moles

<u>Step 6:</u> Calculate Molarity of NH4+

Molarity = Moles / volume

Molarity of NH4+ = 0.063 moles / 0.250 L

Molarity of NH4+ = 0.252 M

The molarity of the final ammonium cation is 0.252M

5 0
3 years ago
(10 points) A student gathers the following data for the freezing point depression of a pure solvent and solvent-solute solution
Alex17521 [72]

Answer:

548 g/mol

Explanation:

The freezing point depression of a solvent occurs when a nonvolatile solute is added to it. Because of the interactions between solute-solvent, it is more difficult to break the bonds, so the phase change will need more energy, and the freezing point will drop, which is called cryoscopy.

The drop in temperature can be calculated by:

ΔT = Kf*W*i

Where Kf is the cryoscopy constant of the solvent, W is the molality, and i is the van't Hoff factor, which indicates the fraction of the solute that dissolves.

The molality represents how much moles (n) of the solute is presented in each kg of the solvent (m2), thus

W = n/m2

The number of moles is the mass of the solute (m1) in g, divided by the molar mass (M1) of it:

W = m1/(M1*m2)

So, by the data:

0.2214 = 0.632/(M1*0.00521)

0.00115M1 = 0.632

M1 = 548 g/mol

6 0
3 years ago
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Snezhnost [94]
Vinegar with cabbage juice would change the color to red so its C
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3 years ago
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