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iren [92.7K]
2 years ago
12

What types of atoms typically form covalent bonds?

Chemistry
1 answer:
morpeh [17]2 years ago
8 0

Answer:

D. Nonmetals with nonmetals, because of difference in electronegativity is below 1.7 ​

Explanation:

The types of atoms that typically form covalent bonds are non-metals with non-metals because of the difference in their electronegativity which is below 1.7.

In some instances, the difference can even be zero when dealing with homonuclear substances.

  • Covalent bond are formed between two or more atoms having low electronegativity differences between them.
  • Each of the atoms share their valence electrons to be able to mimic the noble gases.
  • The participating atoms will put down an unpaired electron to be used in forming a shared pair of electrons between them.
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Describe two ways you could demonstrate an acceleration of 2 meters per second squared?
BaLLatris [955]

Answer:

You could do 88 metars  

Explanation:

7 0
3 years ago
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explain the relationship between the rate of effusion of a gas and its molar mass. methane gas (ch4) effuses 3.4 times faster th
Musya8 [376]

The molar mass of the unknown gas is 184.96 g/mol

<h3>Graham's law of diffusion </h3>

This states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass i.e

R ∝ 1/ √M

R₁/R₂ = √(M₂/M₁)

<h3>How to determine the molar mass of the unknown gas </h3>

The following data were obtained from the question:

  • Rate of unknown gas (R₁) = R
  • Rate of CH₄ (R₂) = 3.4R
  • Molar mass of CH₄ (M₂) = 16 g/mol
  • Molar mass of unknown gas (M₁) =?

The molar mass of the unknown gas can be obtained as follow:

R₁/R₂ = √(M₂/M₁)

R / 3.4R = √(16 / M₁)

1 / 3.4 = √(16 / M₁)

Square both side

(1 / 3.4)² = 16 / M₁

Cross multiply

(1 / 3.4)² × M₁ = 16

Divide both side by (1 / 3.4)²

M₁ = 16 / (1 / 3.4)²

M₁ = 184.96 g/mol

Learn more about Graham's law of diffusion:

brainly.com/question/14004529

#SPJ1

3 0
2 years ago
Convert 0.02 g/mL to the unit g/L.
Elenna [48]
I don't know but I think that 0.02 g/mL is 20 g/L because you multiply the 0.02 by a 100. That's how you get the Gram liter
4 0
3 years ago
The reaction AgNO3(aq) + NaCl(aq) → AgCl(s) + NaNO3(aq) is a(n) ______________ reaction.
Temka [501]

Answer : The correct option is, (e) precipitation reaction

Explanation :

Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

Precipitation reaction : It is defined as the reaction in which an insoluble salt formed when two aqueous solutions are combined.

The insoluble salt that settle down in the solution is known an precipitate.

Single replacement reaction : A chemical reaction in which the more reactive element replace the less reactive element.

It is represented as,

A+BC\rightarrow AC+B

In this reaction, A is more reactive element and B is less reactive element.

Acid-base reaction : It is defined as the reaction in which an acid react with a base to give salt and water as a product.

The given chemical reaction is:

AgNO_3(aq)+NaCl(aq)\rightarrow AgCl(s)+NaNO_3(aq)

This reaction is a precipitation reaction in which the two aqueous solution silver nitrate and sodium chloride combined to give sodium nitrate solution and silver chloride as a precipitate. In precipitation reaction there is no changes in oxidation state of the element.

Hence, the correct option is, (e) precipitation

8 0
3 years ago
Which of the following statements about the elements in group 2 of the periodic table is true?
stiks02 [169]

Answer:

they all have two electrons in their outermost shell

8 0
2 years ago
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