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iren [92.7K]
2 years ago
12

What types of atoms typically form covalent bonds?

Chemistry
1 answer:
morpeh [17]2 years ago
8 0

Answer:

D. Nonmetals with nonmetals, because of difference in electronegativity is below 1.7 ​

Explanation:

The types of atoms that typically form covalent bonds are non-metals with non-metals because of the difference in their electronegativity which is below 1.7.

In some instances, the difference can even be zero when dealing with homonuclear substances.

  • Covalent bond are formed between two or more atoms having low electronegativity differences between them.
  • Each of the atoms share their valence electrons to be able to mimic the noble gases.
  • The participating atoms will put down an unpaired electron to be used in forming a shared pair of electrons between them.
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Which statements describe an element? Check all that apply.
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The equilibrium of 2H 2 O(g) 2H 2 (g) + O 2 (g) at 2,000 K has a Keq value of 5.31 x 10-10. What is the Keq expression for this
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Answer:

5.31*10^{-10} = \frac{[]H_{2}]^{2}[O_{2}]}{[H_{2}O]^{2}}

Explanation:

For a chemical reaction, equilibrium is a state at which the rate of the forward reaction equals that of the reverse reaction. The equilibrium constant Keq is a parameter characteristic of this state which is expressed as a ratio of the concentration of the products to that of the reactants.

For a hypothetical reaction:

xA + yB ⇄ zC

The equilibrium constant is :

Keq = \frac{[A]^{x}[B]^{y}}{[C]^{z} }

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2H_{2}O\rightleftharpoons 2H_{2} + O_{2}

The equilibrium constant is expressed as :

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Since Keq = 5.31*10^-10

5.31*10^{-10} = \frac{[]H_{2}]^{2}[O_{2}]}{[H_{2}O]^{2}}

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2 years ago
Read 2 more answers
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