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2 years ago

A baseball pitcher has 60 2/3 innings. what is the number of innings written as a decimal?

Mathematics

1 answer:

Arturiano [62]2 years ago

6 0

Answer:

The number of innings, as a decimal, is 60.67 innings.

Step-by-step explanation:

While 2/3 is technically 0.666666.... and continues on forever, making it shorter is easier to visualize and most likely what you'll see on future math problems.

You might be interested in

There are 45 students in Lisa's class. 35 of the students are boys and rest are girls

geniusboy [140]

If the question is how many students are girls, than it's ten(10).

8 0

2 years ago

Find the equation of a line that passes through (1,12) and is parallel to the graph of y=3x+3 Write the equation in slope-inter

Ray Of Light [21]

Answer:

The equation of the parallel line is

y = 3x + 9

Step-by-step explanation:

The general equation of a straight line is given as;

y = mx + c

where m is the slope and c is the intercept

If two lines are parallel, their slopes are equal

So the slope of the new line too is 3

Using the point-slope formula

y-y1 = m(x-x1)

y-12 = 3(x-1)

y-12 = 3x-3

y = 3x-3 + 12

y = 3x + 9

5 0

2 years ago

3. A wall is 12 feet high. If its area is 132 sq ft, what is its

dalvyx [7]

B. 46 feet because 132/12=11 and 12+12+11+11=46

5 0

2 years ago

At a country concert, the ratio of number of boys to the number of girls is 2:7. If there are 250 more girls than boys, how many

Juliette [100K]

Answer:

100 boys at the concert

Step-by-step explanation:

When changing the ratio between the number of boys to the number of girls, it always has to be equivalent to the original ratio 2:7

So, convert the ratio 2:7 to a different ratio, but it still has to be equivalent to the ratio 2:7. By doing that, multiply both sides of the 2:7 ratio by 50:

2 : 7

×50 ×50

To get:

100:350 ⇒ This ratio means that the ratio between the number of boys to the number of girls is now 100:350, but that’s okay to have because it’s still equivalent to the original 2:7 ratio.

So, using the new ratio 100:350, this means that there are 100 boys at the concert and 350 girls at the concert, and 350 is 250 more than 100 which proves what the question is asking. So there are 100 boys at the concert.

<u>Answer:</u> 100 boys at the concert

<em>I hope you understand and that this helps with your question! </em>:)

7 0

2 years ago

Find two power series solutions of the given differential equation about the ordinary point x = 0. compare the series solutions

monitta

I don't know what method is referred to in "section 4.3", but I'll suppose it's reduction of order and use that to find the exact solution. Take $z=y'$ , so that $z'=y''$ and we're left with the ODE linear in $z$ :

$y''-y'=0\implies z'-z=0\implies z=C_1e^x\implies y=C_1e^x+C_2$

Now suppose $y$ has a power series expansion

$y=\displaystyle\sum_{n\ge0}a_nx^n$
$\implies y'=\displaystyle\sum_{n\ge1}na_nx^{n-1}$
$\implies y''=\displaystyle\sum_{n\ge2}n(n-1)a_nx^{n-2}$

Then the ODE can be written as

$\displaystyle\sum_{n\ge2}n(n-1)a_nx^{n-2}-\sum_{n\ge1}na_nx^{n-1}=0$

$\displaystyle\sum_{n\ge2}n(n-1)a_nx^{n-2}-\sum_{n\ge2}(n-1)a_{n-1}x^{n-2}=0$

$\displaystyle\sum_{n\ge2}\bigg[n(n-1)a_n-(n-1)a_{n-1}\bigg]x^{n-2}=0$

All the coefficients of the series vanish, and setting $x=0$ in the power series forms for $y$ and $y'$ tell us that $y(0)=a_0$ and $y'(0)=a_1$ , so we get the recurrence

$\begin{cases}a_0=a_0\\\\a_1=a_1\\\\a_n=\dfrac{a_{n-1}}n&\text{for }n\ge2\end{cases}$

We can solve explicitly for $a_n$ quite easily:

$a_n=\dfrac{a_{n-1}}n\implies a_{n-1}=\dfrac{a_{n-2}}{n-1}\implies a_n=\dfrac{a_{n-2}}{n(n-1)}$

and so on. Continuing in this way we end up with

$a_n=\dfrac{a_1}{n!}$

so that the solution to the ODE is

$y(x)=\displaystyle\sum_{n\ge0}\dfrac{a_1}{n!}x^n=a_1+a_1x+\dfrac{a_1}2x^2+\cdots=a_1e^x$

We also require the solution to satisfy $y(0)=a_0$ , which we can do easily by adding and subtracting a constant as needed:

$y(x)=a_0-a_1+a_1+\displaystyle\sum_{n\ge1}\dfrac{a_1}{n!}x^n=\underbrace{a_0-a_1}_{C_2}+\underbrace{a_1}_{C_1}\displaystyle\sum_{n\ge0}\frac{x^n}{n!}$

4 0

2 years ago