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2 years ago

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Find the rule and the graph of the function whose graph can be obtained by performing the translation 3 units left and 2 units d

own on the parent function f(x)=x^3

1 answer:

ahrayia [7]2 years ago

5 0

Answer: Option b.

Step-by-step explanation:

1. You have the following parent function given in the problem above:

f(x)=x³ (This is the simplest form. We need to translate it 3 units left and 2 units down)

2. If you take the parent function and make y=f(x+3), then you have:

$y=f(x+3)=(x+3)^{3}$ (The function is shifted 3 units left on the x-axis).

3. Then you if you make y=f(x+3)-2, as following, you obtain:

$y=f(x+3)-2=(x+3)^{3}-2$ (The function is shifted 2 units down on the y-axis).

4. Therefore, that is how you obtain the final function.

The answer is the graph shown in the option b.

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<h3><u>Let's</u><u> </u><u>understand the concept</u><u>:</u><u>-</u></h3>

Here angle B is 90°

So $\triangle ABC$ and $\triangle ABD$ Are right angled triangle

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<h3><u>Required Answer</u><u>:</u><u>-</u></h3>

First in triangle ABC

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Hypontenuse =h =10cm

We need to find base=b

According to Pythagoras thereon

${\boxed{\sf b^2=h^2-p^2}}$

Substitutethe values

$\longrightarrow$ $\sf b^2=10^2-p^2$

$\longrightarrow$ $\sf b={\sqrt {10^2-8^2}}$

$\longrightarrow$ $\sf b={\sqrt{100-64}}$

$\longrightarrow$ $\bf b={\sqrt {36}}$

$\longrightarrow$ $\sf b=6$

$\therefore$ $\overline{BC}=6cm$

BD=BC+CD

$\longrightarrow$ $BD=9+6$

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Now in $\triangle ABD$

Perpendicular=p=8cm

Base =b=15cm

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${\boxed {\sf h^2=p^2+b^2}}$

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