Answer:
The height of the cone is 10.9 cm
Step-by-step explanation:
step 1
Find the height of the cone
Applying the Pythagoras Theorem
therefore
The height of the cone is 10.9 cm
Beautiful ! What a great exercise ! I won't even check to verify
that 1:10⁻¹⁹ is an appropriate scale to map the Milky Way onto a
football field. I'll just accept it and go from there.
(4.4 light years) x (10⁻¹⁹) = (2.5848 x 10¹³ miles) x (10⁻¹⁹)
= 2.5848 x 10⁻⁶ mile
= 0.164 inch .
(1,391,400 kilometers) x (10⁻¹⁹) = 1.3914 x 10⁻¹⁰ meter
Research Conclusions:
If the Milky Way shrinks to fit on a football field, then
-- Alpha Centauri is 0.164 inch from us.
-- The sun's diameter is about 1.39 times that of a Hydrogen atom.
Playing with this same fun concept a little more:
-- The Earth is sailing around in its orbit, once a year,
about 0.000015 millimeter from the sun.
-- It takes light almost 27 years to travel 1 inch !
wow !
Yes, the table represents a function.
None of the independent (x) values are repeated and each one has a corresponding (y) value.
If you had a repeated (x) value in the table, it would not represent a function.
Answer:
D:) (2,2,) is the Answer
Step-by-step explanation:
Solve the following system:
{X - 2 Y = -2 | (equation 1)
{3 X - 2 Y = 2 | (equation 2)
Swap equation 1 with equation 2:
{3 X - 2 Y = 2 | (equation 1)
{X - 2 Y = -2 | (equation 2)
Subtract 1/3 × (equation 1) from equation 2:
{3 X - 2 Y = 2 | (equation 1)
{0 X - (4 Y)/3 = (-8)/3 | (equation 2)
Multiply equation 2 by -3/4:
{3 X - 2 Y = 2 | (equation 1)
{0 X+Y = 2 | (equation 2)
Add 2 × (equation 2) to equation 1:
{3 X+0 Y = 6 | (equation 1)
{0 X+Y = 2 | (equation 2)
Divide equation 1 by 3:
{X+0 Y = 2 | (equation 1)
{0 X+Y = 2 | (equation 2)
Collect results:
Answer: {X = 2 , Y = 2
It’s -4 because you need to like distribute then add like terms, etc.
