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Naddik [55]
4 years ago
7

Calculate the equivalent resistance for both circuits.

Physics
1 answer:
Allisa [31]4 years ago
5 0

Answer:

Series equivalent resistance: R_{eq} = 6  \Omega

Parallel equivalent resistance: R_{eq}=14\Omega

Explanation:

The equivalent resistance in series circuit is calculated as

R_{eq} = R_{1} + R_{2}

R_{eq} = 2 + 4

R_{eq} = 6  \Omega

The equivalent resistance in parallel circuit is calculated as

\frac{1}{R_{eq}} = \frac{1}{R_{1}}+\frac{1}{R_{2}}

Which can be simplified to

R_{eq}=\frac{R_{1}\times R_{2}}{R_{1}+R_{2}}

R_{eq}=\frac{21\times 42}{21+42}

R_{eq}=14\Omega

The parallel circuit has the higher equivalent resistance as compared to series circuit.

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Answer:

Before:

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Explanation:

<u>Conservation of Momentum</u>

Two objects of masses m1 and m2 moving at speeds v1o and v2o respectively have a total momentum of

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m_1=2000\ kg

m_2=1000\ kg\\v_{1o}=8.2\ m/s\\v_{2o}=0\ m/s\\v_{1f}=4\ m/s

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b) Before the collision

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p_{car}=1000\cdot 0=0\ kg.m/s

c) After collision

p_{truck}=2000\cdot 4=8000\ kg.m/s

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\displaystyle v_{2f}=\frac{ 16400+0 -8000 }{ 1000 }

v_{2f}=8.4\ m/s

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p_{car}=1000\cdot 8.4=8400\ kg.m/s

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J_1=\Delta p_1=2000(4-8.2)=-8400 \N.s

The force can be computed as

\displaystyle F=\frac{J}{t}=-\frac{8400}{0.9}=-9333.33 \ Nw

The force on the car has the same magnitude and opposite sign

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