Answer:
Explanation:
Given:
Steam Mass rate, ms = 1.5 kg/min
= 1.5 kg/min × 1 min/60 sec
= 0.025 kg/s
Air Mass rate, ma = 100 kg/min
= 100 kg/min × 1 min/60 sec
= 1.67 kg/s
A.
Extracting the specific enthalpy and temperature values from property table of “Saturated water – Pressure table” which corresponds to temperature at 0.07 MPa.
xf, quality = 0.9.
Tsat = 89.9°C
hf = 376.57 kJ/kg
hfg = 2283.38 kJ/kg
Using the equation for specific enthalpy,
hi = hf + (hfg × xf)
= 376.57 + (2283.38 × 0.9)
= 2431.552 kJ/kg
The specific enthalpy of the outlet, h2 = hf
= 376.57 kJ/kg
B.
Rate of enthalpy (heat exchange), Q = mass rate, ms × change in specific enthalpy
= ms × (hi - h2)
= 0.025 × (2431.552 - 376.57)
= 0.025 × 2055.042
= 51.37455 kW
= 51.38 kW.
F=W=mg
12N(given)= m*9.8
m= 1.22 kg
Answer:
Mount Rushmore is a very well built sculpture. It is visited by millions of people each year to see 60-foot tall images of the American presidents; George Washington, Thomas Jefferson, Abraham Lincoln and Theodore Rosevelt which are carved into the Black Hills of South Dakota. Mount Rushmore has faced many controversies too. The land it was built on is sacred to Native Americans. The Sioux were also forced to leave the land, after lots of battles
Explanation:
<span>59.027m/s^2
Centripetal force is give by F = mv^2/r
Since
F = ma
The acceleation accoiated with this centripetal force is
a=v^2/r
the radius is found by r=d/2=5.75m
velocity is found by
v=d/t
distance is the circumference of the circle
c=pi*d=11.5*3.14=36.11m
time=60s/30.6rpm=1.96s
v=36.11/1.96=18.423m/s
plugging this back in to
a=v^2/r=(18.423m/s)^2/5.75m=59.027m/s^2</span>
Answer:
Filiberto experimenta una deceleración de 
.
Explanation:
(The problem was written in Spanish. Hence, explanation will be held in Spanish).
Asúmase que Filiberto se distrae por 2 segundos, puesto que un par equivale a dos, y que el vehículo experimenta un aceleración constante. La deceleración experimentada por el vehículo se deriva de la siguiente fórmula:
Filiberto experimenta una deceleración de .
