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cupoosta [38]
3 years ago
5

Filiberto va a 90m/s en su carri, de repente se distrae por un par de segundos y su velocdad pasa a 40 m/s ¿cual fue su acelerac

ion de su movimientonto
Physics
1 answer:
svet-max [94.6K]3 years ago
7 0

Answer:

Filiberto experimenta una deceleración de 2\,\frac{m}{s^{2}}.

Explanation:

(The problem was written in Spanish. Hence, explanation will be held in Spanish).

Asúmase que Filiberto se distrae por 2 segundos, puesto que un par equivale a dos, y que el vehículo experimenta un aceleración constante. La deceleración experimentada por el vehículo se deriva de la siguiente fórmula:

a = \frac{v-v_{o}}{\Delta t}

a = \frac{40\,\frac{m}{s}-90\,\frac{m}{s} }{2\,s}

a = -25\,\frac{m}{s^{2}}

Filiberto experimenta una deceleración de 2\,\frac{m}{s^{2}}.

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From the gravitational law calculate the weight W (gravitational force with respect to the earth) of a 89-kg man in a spacecraft
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Answer:

W=\frac{773}{4.45}=173.76 l b f

Explanation:

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The law of gravitation

G=6.673\left(10^{-11}\right) m^{3} /\left(k g \cdot s^{2}\right)

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h=261 \mathrm{~km} \quad[\mathrm{~km}]

ESULT W=\frac{6.673\left(10^{-11}\right) \cdot 5.976\left(10^{24}\right) \cdot 89}{\left(6371 \cdot 10^{3}+261 \cdot 10^{3}\right)^{2}}=773.22 \mathrm{~N}

W=\frac{773}{4.45}=173.76 l b f

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