a thunderclap sends a sound wave through the air and the ocean below The thunderclap sound wave has a constant frequency of 50 H
1 answer:
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The man can survive, and he lands 12.1 m from the base of the cliff (into the lake)
Explanation:
The motion of the person is equivalent to the motion of a projectile, which consists of two separate motions:
- A uniform motion (constant velocity) along the horizontal direction
- An accelerated motion with constant acceleration (acceleration of gravity) in the vertical direction
We start by analyzing the vertical motion, to find the time it take for the person to reach the ground level. We can use the following suvat equation:
where
s = 50 m is the vertical distance covered (the height of the cliff)
u = 0 is the initial vertical velocity
is the acceleration of gravity
t is the time of flight
Solving for t,
The person moved horizontally at a constant speed of
So, the horizontal distance covered by the man during his flight will be
So, the man will land on the lake (which starts from 12 m), so he can survive.
Learn more about projectile motion:
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Answer:
a) -3.267 m/s
b) 2.227 m/s
Explanation:
As per the conservation of momentum
m1v1 + m2v2=0
m1= mass of log
m2 = mass of lumber jack
v1 = velocity of log
v2 = velocity of lumber jack
a) Velocity of first log
m/s
b) m1v1 + m2v2 = m3v3
Velocity of log
=