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11111nata11111 [884]
3 years ago
14

a thunderclap sends a sound wave through the air and the ocean below The thunderclap sound wave has a constant frequency of 50 H

z​
Physics
1 answer:
Montano1993 [528]3 years ago
4 0

Answer:

child protective services

Explanation:

amonbgus

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If an object on a horizontal frictionless surface is attached to a spring, displaced, and then released, it will oscillate. It i
Kaylis [27]

Answer:

a.0.120mm

b.1.58s

c.0.6329Hz

Explanation:

a. Given that 0.120mm is displaced from equilibrium, 0.120mm after 0.790s on opposite side:

-The amplitude is the maximum displacement from equilibrium.

-The object goes from x=+A to x=-A and back during one cycle.

#Hence, the amplitude of the motion is 0.120mm

b.Motion from maximum positive displacement to maximum negative displacement takes places during half the period of Simple Harmonic Motion(SHM)

0.790s=T/2\\\\T=0.790s\times 2\\\\T=1.58s

#Hence, the period of the motion is 1.58s

c. Frequency is calculated as one divided by the period of the motion.

From b above we know that the motions period is 1.58s

Therefore:

<em>Frequency=1/period=1/1.58=0.6329Hz</em>

<em>#</em><em>The frequency of the motion is </em><em>0.6329Hz</em>

3 0
3 years ago
A lumberjack (mass = 103 kg) is standing at rest on one end of a floating log (mass = 277 kg) that is also at rest. The lumberja
Lorico [155]

Answer:

Explanation:

Given

mass of lumber jack m_L=1000 kg

mass of floating log m_f=277 kg

velocity of lumber jack =3.74 m/s (w.r.t. shore)

conserving momentum

Initial momentum=Final momentum

0=m_L\times 3.74+m_f\times v

v=-\frac{1000\times 3.74}{277}

v=-13.501 m/s

(b)For second Log

Conserving Momentum

Initial momentum of log and Lumber jack=Final momentum of log and lumberjack

m_L\times 3.74=(m_L+m_f)u

u is final velocity of lumberjack and log

u=\frac{m_L}{m_L+m_f}\times 3.74

u=\frac{1000}{1000+277}=2.92 m/s

5 0
4 years ago
A car has a speed of 2 m/s and a mass of 1500 kg. What is the cars kinetic energy?
Kay [80]

Answer:

B

Explanation:

E = mv² / 2

E = (1500kg)(2 m/s)² / 2

E = 6000 J / 2

E = 3000 J

5 0
4 years ago
Read 2 more answers
How much work is done by the force lifting a 0.1-kilogram hamburger vertically upward at a constant velocity 0.3 meter from a ta
pychu [463]

Answer:

0.2943 Nm

Explanation:

Work done is given a the product of force and diatance moved and expressed by the formula

W=Fd

Here W represent work, F is applied force and d is perpendicular distance

Also, we know that F=mg where m is the mass of an object and g is acceleration due to gravity. Substituting this back into the initial equation then

W=mgd

Taking acceleration due to gravity as 9.81 m/s2 and substituting mass with 0.1 kg and distance with 0.3 m then

W=0.1*9.81*0.3=0.2943 Nm

5 0
3 years ago
About how long will a 2-m¤ star live as a main-sequence star quizle
tia_tia [17]
It's mass and its age.
About how long will a 2-M star live as a main-sequence star.
1 billion years.
<span>A low mass red giant star's energy comes from.</span>
8 0
3 years ago
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