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hodyreva [135]
3 years ago
5

Give me this same text but if it was a 7th grader

Physics
2 answers:
-Dominant- [34]3 years ago
7 0

Answer:

This should help!

What is 7th Grade Writing?

In Grade 7, students refine and build upon previously learned knowledge and skills in increasingly complex essays. On a regular basis, 7th grade students are expected to produce clear, coherent, and focused essays that are error-free. Seventh grade students are able to select and use different forms of writing for specific purposes such as to inform, persuade, or entertain. Students vary sentence structure and use verb tenses appropriately and consistently such as present, past, future, perfect, and progressive. Seventh grade students edit their writing based on their knowledge of grammar and usage, spelling, punctuation, and other conventions of written language. Seventh-graders use every phase of the writing process and continue to build their knowledge of writing conventions. Students draw data from multiple primary and secondary sources for use in research reports and projects.

The following writing standards represent what states* typically specify as 7th grade benchmarks in writing proficiency:

Grade 7: Writing Process

Seventh grade writing standards focus on the writing process as the primary tool to help students become independent writers. In Grade 7, students are taught to use each phase of the process as follows:

Prewriting: In grade 7, students generate ideas from multiple sources and use organizational strategies and tools such as technology, graphic organizers, notes, and outlines. Students choose the form of writing that best suits the intended purpose and then make a plan for writing that prioritizes ideas, addresses purpose, audience, main idea, and logical sequence.

Drafting: In seventh grade, students develop drafts by categorizing ideas, organizing them into paragraphs, and blending paragraphs within larger units of text. Writing exhibits the students’ awareness of the audience and purpose. Essays contain formal introductions, ample supporting details (e.g., facts, statistics, examples, anecdotes), and conclusions. Students analyze language techniques of professional authors, including concrete and abstract word choices, and infusing a variety of language techniques to reinforce voice.

Revising: In seventh grade, students revise selected drafts by elaborating, deleting, combining, and rearranging text. Goals for revision include improving coherence, progression, and the logical support of ideas and content. Grade 7 revision techniques include adding transitional words between sentences to unify important ideas and creating interest by using a variety of sentence structures (including the use of participles and participial phrases at the beginning and end of sentences). Students also evaluate drafts for voice, point of view, and precision of vocabulary. Seventh-graders use creative language devices, and modify word choices using resources and reference materials (e.g., dictionary, thesaurus).

Editing: Students edit their writing to ensure standard usage, varied sentence structure, and appropriate word choice (e.g., eliminating slang). Seventh-graders proofread for grammar, punctuation, capitalization, and spelling, using reference materials, word processors, and other resources.

Publishing: Using technology, seventh-graders refine and “publish” their work frequently in a format appropriate to the audience and purpose (e.g., manuscript, multimedia). Published pieces use appropriate formatting and graphics (e.g., tables, drawings, charts, graphs) when applicable to enhance the appearance of the document.

<h2>pls brailiest!</h2>

jarptica [38.1K]3 years ago
4 0

Answer:

Mount Rushmore is a very well built sculpture. It is visited by millions of people each year to see 60-foot tall images of the American presidents; George Washington, Thomas Jefferson, Abraham Lincoln and Theodore Rosevelt which are carved into the Black Hills of South Dakota. Mount Rushmore has faced many controversies too. The land it was built on is sacred to Native Americans. The Sioux were also forced to leave the land, after lots of battles

Explanation:

You might be interested in
A goal should NOT be:
Korvikt [17]

Answer: unspecific

Explanation:

you should always be specific with your goals, say someones goal is to make it to state for swimming, he/she should be specific to the event in which they want to go to state in.

6 0
3 years ago
A tow truck drags a stalled car along a road. The chain makes an angle of 30???? with the road and the tension in the chain is 1
My name is Ann [436]

Answer: work = 1,305kJ

Explanation:

angle= 30°

force= 1,500N

distance= 1,000m

The formula for work is : Work= force x distance, however there is an angle of 30° between the direction of force applied and the direction of motion, therefore force must be decomposed to its value on the horizontal axis which is the direction of motion by using the cosine of the very angle.

W= F×cos(α)×D

W= 1,500×cos (30)×1,000

W= 1,305kJ ( kilojoules)

3 0
3 years ago
The acceleration due to gravity on Jupiter is 2.5 times what it is here on earth. An object weighing 347.9 N here on earth will
inessss [21]

Answer:  weight on Jupiter = 869.75 N

              mass  on Earth = mass on Jupiter = 35.5 Kg

Explanation:

W = mg

W = weight

m = mass

g = gravitational acceleration [ on the Earth, g₁ = 9,8 N/kg ]

On the Earth,

G₁ = m x g₁  = 347,9 N

On the Jupiter,

G₂ = mg₂  

mass on the Earth = mass on the Jupiter !  

m = G₁ : g = 347.9 N : 9,8 N/kg = 35.5 kg

G2 : G1 = 2.5

G₂ = 2,5 G₁ = 2,5 x 347.9 N =  869,75 N

5 0
3 years ago
Find the angle formed by two forces of 7N and 15N respectively if its result is worth 20N
nadezda [96]
First, you need to make certain assumptions before solving this question. Why? Because there are no information given about the direction of these forces. In such questions as above, ALWAYS make the following assumptions:

1) Take first force, say F_{1}, and assume that it is pointing towards the x-direction.

Let us take the 7N force! By keeping the above assumption in our minds, the force vector would be like:
F_{1} = 7i, where i = Unit vector in the x-direction.

2) Take the second force, say F_{2}, and assume that it is making an angle \alpha with the first force F_{1}.

Let us take the 15N force! By keeping the above assumption in our minds, the forces vector would be like:

F_{2} = (15*cos \alpha)i + (15*sin \alpha )j

Now from simple vector addition, we know that,
F_{R} = F_{1} + F_{2} --- (A)

Where F_{R} = Resultant vector.
NOTE: In equation (A), all forces are in vector notation. Assume that there is an arrow head on top of them.

Let us find F_{1}+F_{2} first!
F_{1}+F_{2} =  7i+(15*cos \alpha)i + (15*sin \alpha )j

=> F_{1}+F_{2} =  (7+15*cos \alpha)i + (15*sin \alpha )j

Now the magnitude of F_{1}+F_{2} is,
| F_{1}+F_{2}| = \sqrt{ (7+ 15*cos \alpha)^{2} +  (15*sin \alpha )^{2}}

=> | F_{1}+F_{2}| = \sqrt{ 49 + 225*(cos \alpha)^{2} + 210*(cos \alpha)+ 255*(sin \alpha )^{2}}

Since (sin \alpha)^{2} + (cos \alpha)^{2} = 1, therefore,

=> | F_{1}+F_{2}| = \sqrt{ 49 + 225 + 210*(cos \alpha)}

Since  | F_{1}+F_{2}| = |F_{R}|, and the magnitude of the resultant force is 20N, therefore,

 |F_{R}| = | F_{1}+F_{2}|
20 = \sqrt{ 49 + 225 + 210*(cos \alpha)}

Take square on both sides,
400 = 49 + 225 + 210*(cos \alpha)
(cos \alpha) =  \frac{3}{5}

\alpha = 53.13^{o}

Ans: Angle formed by the two forces, 7N and 15N, is: 53.13°

-israr

4 0
3 years ago
Rearrange the equation to solve for the permeability of free space (μ0). Remember that the slope is the ratio of magnetic field
IRINA_888 [86]

Complete Question

The complete question is shown on the first uploaded image

Compare the percent error between your value and the accepted value of 1.26 times 10-6 T · m/A. (Use the accepted value given to three significant figures in your calculation.). 100% % error = %

Answer:

The permeability of free space is \mu_0 = 1.32*10^{-6} \ Tm/A

The percentage error is  % error = 5.25%

Explanation:

From the question we are told that

            The slope is  s= 3.9\  G/A , and

Generally  1 \ gauss =  10^{-4 } tesla

               So  s = 3.9 *10^ {-4} T /A

From the relation given in the question

                        \mu_0 = \frac{2R}{N} [\frac{B}{I} ]

 Where R is the radius of the coil  =\frac{Diameter \ of \ coil }{2} = 0.017m

             N is the number of loops of the coil = 10

Now from the question we are told that

                  s = \frac{B}{I}

substituting into the equation above

               \mu_0 = \frac{2R }{N} s

Substituting values

              \mu_0= \frac{2 * 0.017}{10 } * 3.9*10^{-4}

                   = 1.326 *10^ {-6} \ Tm/A

Generally the % error is mathematically represented as

                    %error = \frac{Measured \  value - accepted \ value}{accepted \  value } *100

Given that the accepted value is \mu_o_ {acc} = 1.26 *10 ^{-6} \ T \cdot m /A

      Hence substituting values

                      %error  = \frac{(1.326-1.26)*10^{-6}}{1.26 *10 ^ {-6}} *100

                                  = 5.24

6 0
4 years ago
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