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Arturiano [62]
3 years ago
8

Assuming that the collision factor remains the same, by how much must an enzyme lower the activation energy of the reaction in o

rder to achieve a 5×105-fold increase in the reaction rate?
Biology
2 answers:
Natalka [10]3 years ago
8 0

Answer:

By the same amount

Explanation:

The activation energy and the rate of a reaction rate is closely related to each other. The higher is the activation energy, the lower will the rate of chemical reaction.

Thus, if rate is to be increased by 5×105-fold then the activation energy must be lowered by the same factor as these two entities are inversely proportional to each other

Anestetic [448]3 years ago
3 0
(8.314 J/molK)(310K)ln(3E5) = E-EcatE-Ecat 
<span>=32504.22 J/mol = 32.504 KJ/mol (pay attention to any requirement on sig fig)

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
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