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Elena-2011 [213]
3 years ago
5

Traveling waves are generated on a string fixed at both ends. The string has a length L, a linear mass density m, and a tension

T. Which of the following will cause the wave speed to increase?
I. Using the same string but increasing the tension.
II Using a longer string with the same μ and T.
III. Using a string with the same L and T but a smaller μ.

a. I only
b. II only
c. III only
d. I or II
d. I or III
Physics
1 answer:
bagirrra123 [75]3 years ago
8 0

Answer: d. I or II

Explanation: A traveling wave has speed that depends on characteristics of a medium. Characteristics like linear density (μ), which is defined as mass per length.

Tension or Force (F_{T}) is also related to the speed of a moving wave.

The relationship between tension and linear density and speed is ginve by the formula:

|v|=\sqrt{\frac{F_{T}}{\mu} }

So, for the traveling waves generated on a string fixed at both ends described above, ways to increase wave speed would be:

1) Increase Tension and maintaining mass and length constant;

2) Longer string will decrease linear density, which will increase wave speed, due to their inversely proportional relationship;

Then, ways to increase the wave speed is

I. Using the same string but increasing tension

II. Using a longer string with the same μ and T.

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Which describes why the magma moves in the direction of the arrows?
Musya8 [376]

The magma is heated and becomes less dense by the core moving it toward the crust.

Option D.

<u>Explanation:</u>

Magma is a form of molten rock which might be partially molten or might be fully molten. Magma consists of silicate liquid.

This molten part of the rock is either ejected in the form of lava or this molten rock might move from upper layer of Earth to the lower layer of Earth. The crystals which are not molten which get transported into the magma, form bubbles and get separated.

7 0
3 years ago
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An 1120 kg car traveling at 17 m/s is brought to a stop while skidding 40 m. Calculate the work done on the car by friction forc
sergij07 [2.7K]

Answer:

Approximately (-1.6 \times 10^{5}\; \rm J) (assuming that the car was on level ground.)

Explanation:

When an object of mass m is moving at a speed of v, the kinetic energy of that object would be (1/2) \, m \cdot v^{2}.

Initial kinetic energy of the car:

\begin{aligned}&\frac{1}{2}\, m \cdot v^{2} \\ &= \frac{1}{2}\times 1120\; \rm kg \times (17\; \rm m \cdot s^{-1})^{2} \\ &\approx 1.6\times 10^{5}\; \rm J \end{aligned}.

After the car comes to a stop, the kinetic energy of this car would be 0\; \rm J because the car would not be moving.

Change to the kinetic energy of the car: \text{Final KE} - \text{Initial KE} = -1.6 \times 10^{5}\; \rm J.

If the car is traveling on level ground, friction would be the only force that contributed to this energy change. Hence:

\text{Work of friction} = \text{Energy change} = -1.6\times 10^{5}\; \rm J.

The value of the work that friction did is negative. The reason is that at any instant before the car comes to a stop, friction would be exactly opposite to the direction of the movement of the car.

The work of a force on an object is the dot product of that force and the displacement of that object. The dot product of two vectors of opposite directions is negative. Hence, in this question, the work that friction did on the car would be negative because the friction vector would be opposite to the movement of the car.

6 0
3 years ago
A small glider is coasting horizontally when suddenly a very heavy piece of cargo falls out of the bottom of the plane.
myrzilka [38]

Answer:

a. The plane speeds up but the cargo does not change speed.

Explanation:

Just to make it clear, the question is as follows from what I understand.

A small glider is coasting horizontally when suddenly a very heavy piece of cargo falls out of the bottom of the plane.  You can neglect air resistance.

Just after the cargo has fallen out:

a. The plane speeds up but the cargo does not change speed.

b. The cargo slows down but the plane does not change speed.

c. Neither the cargo nor the plane change speed.

d. The plane speeds up and the cargo slows down.

e. Both the cargo and the plane speed up.

And we are requested to choose the right answer under the given conditions. We know the glider has no motor, then it must be in free fall movement, then it is experiencing some force that pulls it to the from due to the gravity effect on it, and a force in general is calculated by

F=m*a, m:= mass of the object, a:= acceleration.

Here we are only considering the horizontal effect of the forces, then since the mass is reduced the acceleration must increase to compensate and maintain  the equilibrium of the forces, then the glider being lighter can travel faster due to the acceleration. On the other hand by the time the cargo left the glider there was no acceleration and the speed it had at the moment he left the plane continues, then the cargo does not change its speed, then horizontally speaking the answer would be a. The plane speeds up but the cargo does not change speed.

5 0
3 years ago
ANSWER ASAP
Galina-37 [17]

Answer:

I'm not great at science, but I believe that the answer is elastic potential energy.

Explanation:

Components of mechanical systems store elastic potential energy if they are deformed when forces are applied to the system. Energy is transferred to an object by work when an external force displaces or deforms the object.

6 0
3 years ago
A Roman centurion fires off a vat of burning pitch from
EastWind [94]

Answer:

(a) 1.11sec

(b) 14.37m/s

(c) 31.78m

Explanation:

U = 18m/s, A = 37°, g = 9.8m/s^2

(a) t = UsinA/g = 18sin37°/9.8 = 18×0.6018/9.8 = 1.11sec

(b) Ux = UcosA = 18cos37° = 18×0.7986 = 14.37m/s

(c) R = U^2sin2A/g = 18^2sin2(37°)/9.8 = 324sin74°/9.8 = 324×0.9613/9.8 = 31.78m

6 0
4 years ago
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