Answer:
I don't really know
Explanation:
I really wanted to help you, but then I realized i didnt know how to
Answer:
The force applied to the surface is 9 kilo Newton.
Explanation:
While jumping on the surface the player applies the force that is equal to its weight on the surface.
The mass of the player is given as 90 kg.
Force applied by the player = weight of the player
Force applied by the player = m × g
Where m is the mass of the player and g is acceleration due to gravity
Force applied by the player = 90 × 9.8
Force applied by the player = 882 Newton
Expressing your answer to one significant figure, we get
Force applied by the player =0. 9 kilo Newton
The force applied to the surface is 0.9 kilo Newton.
Answer:
C. crust, mantle, core
Explanation:
density increases as you travel from the crust to the inner core
the crust is on top
next is the mantle
and then the core
Answer:
a) D_ total = 18.54 m, b) v = 6.55 m / s
Explanation:
In this exercise we must find the displacement of the player.
a) Let's start with the initial displacement, d = 8 m at a 45º angle, use trigonometry to find the components
sin 45 = y₁ / d
cos 45 = x₁ / d
y₁ = d sin 45
x₁ = d sin 45
y₁ = 8 sin 45 = 5,657 m
x₁ = 8 cos 45 = 5,657 m
The second offset is d₂ = 12m at 90 of the 50 yard
y₂ = 12 m
x₂ = 0
total displacement
y_total = y₁ + y₂
y_total = 5,657 + 12
y_total = 17,657 m
x_total = x₁ + x₂
x_total = 5,657 + 0
x_total = 5,657 m
D_total = 17.657 i^+ 5.657 j^ m
D_total = Ra (17.657 2 + 5.657 2)
D_ total = 18.54 m
b) the average speed is requested, which is the offset carried out in the time used
v = Δx /Δt
the distance traveled using the pythagorean theorem is
r = √ (d1² + d2²)
r = √ (8² + 12²)
r = 14.42 m
The time used for this shredding is
t = t1 + t2
t = 1 + 1.2
t = 2.2 s
let's calculate the average speed
v = 14.42 / 2.2
v = 6.55 m / s