The correct answer is: 1792g or 1800g.
(When you round it)
Answer:
I = 0.25 [amp]
Explanation:
To solve this problem we must use ohm's law which tells us that the voltage is equal to the product of the current by the resistance.
V = I*R
where:
V = voltage [Volt]
I = amperage or current [amp]
R = resistance [ohm]
Since all resistors are connected in series, the total resistance will be equal to the arithmetic sum of all resistors.
Rt = 2 + 8 + 14
Rt = 24 [ohm]
Now clearing I for amperage
I = V/Rt
I = 6/24
I = 0.25 [amp].
Answer:
A spring whose spring constant is 200 lbf/in has an initial force of 100 lbf acting on it. Determine the work, in Btu, required to compress it another 1 inch.
Step 1 of 4
The force at any point during the deflection of the spring is given by,
where is the initial force
and x is the deflection as measured from the point where the initial force occurred.
The work required to compress the spring is
Therefore work required to compress the spring is
The work required to compress the spring in Btu is calculated by
Where 1Btu =778
The work required to compress the spring,
eman Asked on February 19, 2018 in thermal fluid Sciences 4th solutions.
Explanation:
Answer:
0.240 J/g/°C
Explanation:
q = mCΔT
47.3 cal = (55.00 g) C (15.0°C)
C = 0.0573 cal/g/°C
Usually, specific heat is measured in J/g/°C, so we can convert:
C = 0.0573 cal/g/°C × 4.184 J/cal
C = 0.240 J/g/°C
Answer: True
Explanation: A neutral spherical conducting shell, has no net electric field inside it. The neutral conductor separates its positive and negative charges, when it is kept in a region of electric field, so that the net electric field inside the conductor becomes zero
Let us assume that a spherical Gaussian sphere surrounding the cavity and inside the conductor.
Since electric field inside the conductor doesn't exists, therefore the net electric flux through the Gaussian surface is zero.
From Gauss's law, when net electric flux through the closed surface is zero, the net enclosed charge should be zero
In order to make net enclosed charge as zero inside the metal, the interior surface of the conductor acquires a charge of -q
Since the interior surface of the conductor acquired -q charge, in order to maintain the electrical neutrality of the conductor, the exterior surface of the conductor acquires +q charge on it