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dalvyx [7]
3 years ago
14

What is the force felt by the 64-kg occupant of the car? Express your answer to two significant figures and include the appropri

ate units. Enter positive value if the direction of the force is in the direction of the initial velocity and negative value if the direction of the force is in the direction opposite to the initial velocity. F =
Physics
1 answer:
Yakvenalex [24]3 years ago
5 0

Answer:

The force is -1.67\times10^{5}\ N

Explanation:

Given that,

Mass of car = 64 kg

Suppose,  a 1400-kg car that stops from 34 km/h on a distance of 1.7 cm.

We need to calculate the acceleration

Using formula of acceleration

v^2-u^2=2as

Where, v = final velocity

u = initial velocity

a = acceleration

s = distance

Put the value into the formula

0^2-(34\times\dfrac{5}{18})^2=2\times a\times 1.7\times10^{-2}

a=\dfrac{(34\times\dfrac{5}{18})^2}{2\times1.7\times10^{-2}}

a=-2623.45\ m/s²

We need to calculate the force

Using formula of force

F=ma

F=64\times(-2623.45)

F=-1.67\times10^{5}\ N

Negative sign shows the direction of the force is in the direction opposite to the initial velocity.

Hence, The force is -1.67\times10^{5}\ N

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What two factors are a part of thermohaline circulation
Margarita [4]

Answer:

These deep-ocean currents are driven by differences in the water's density, which is controlled by temperature (thermo) and salinity (haline). This process is known as thermohaline circulation.

Explanation:

7 0
3 years ago
3. An athlete makes a long jump and follows a projectile motion. Air resistance is negligible. Which one of the following statem
yulyashka [42]

Answer:

Option (b) is correct.

Explanation:

The motion under the influence of gravity is called projectile motion.

The acceleration due to gravity is constant through out the motion and it is always acting downwards.

When an athlete jumps and follow the projectile path, it always have the same horizontal velocity as there is no acceleration in the horizontal direction.

Also he has the vertical acceleration constant which is equal to the acceleration due to gravity and acts towards the center of earth.  

Option (b) is correct.

6 0
3 years ago
PLEASE HELP!!!!!
Sunny_sXe [5.5K]
I need to force in order to answer. What is it
3 0
2 years ago
A bus contains a 1440 kg flywheel (a disk that has a 0.63 m radius) and has a total mass of 10200 kg. Calculate the angular velo
CaHeK987 [17]

Answer:\omega =93.51 rad/s

Explanation:

Given

mass of Flywheel m_1=1440 kg

mass of bus m_b=10200 kg

radius of Flywheel r=0.63 m

final speed of bus v=21 m/s

Conserving Energy i.e.

0.9(Rotational Energy of Flywheel)= change in Kinetic Energy of bus

Let \omegabe the angular velocity of Flywheel

0.9\cdot \frac{I\omega ^2}{2}=\frac{m_bv^2}{2}

I=moment\ of\ Inertia =mr^2=1440\cdot 0.63^2=571.536 kg-m^2

0.9\cdot \frac{571.536\cdot \omega ^2}{2}=\frac{10200\cdot 21^2}{2}

\omega ^2=21^2\times \frac{10200}{0.9\times 571.536}

\omega =21\times 4.45=93.51 rad/s

8 0
3 years ago
A load of 800 N is lifted using a block and tackle having 5 pulleys. If the applied effort is 200 N, calculate
ser-zykov [4K]

Explanation:

Load=800N

Effort=200N

1. Mechanical Advantage = LOAD/EFFORT

= 800N/200N

= 4

2 Velocity Ratio = no. Of pulleys =5

3. Efficiency = Mechanical advantage / velocity ratio × 100%

= (4/5)×100%

=80%

4. output work= load×load distance

= 800N × 5m

= 4 × 1000J

5. Efficiency = (output work/input work) ×100%

Or, 80% = (4000J/input work) ×100%

Or, 80%/100% = 4000J/inputwork

Or, 4/5 = 4000J/inputwork

Or, input work =4000J × 5/4

Input work = 5×1000J

I hope it helped! ;-)

8 0
2 years ago
Read 2 more answers
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