Answer:
(a)
(b)
Explanation:
<u>Given:</u>
- = The first temperature of air inside the tire =
- = The second temperature of air inside the tire =
- = The third temperature of air inside the tire =
- = The first volume of air inside the tire
- = The second volume of air inside the tire =
- = The third volume of air inside the tire =
- = The first pressure of air inside the tire =
<u>Assume:</u>
- = The second pressure of air inside the tire
- = The third pressure of air inside the tire
- n = number of moles of air
Since the amount pof air inside the tire remains the same, this means the number of moles of air in the tire will remain constant.
Using ideal gas equation, we have
Part (a):
Using the above equation for this part of compression in the air, we have
Hence, the pressure in the tire after the compression is .
Part (b):
Again using the equation for this part for the air, we have
Hence, the pressure in the tire after the car i driven at high speed is .
Part (a): Magnetic dipole moment
Magnetic dipole moment = IA, I = Current, A = Area of the loop
Then,
Magnetic dipole moment = 2.6*π*0.15^2 = 0.184 Am^2
Part (b): Torque acting on the loop
T = IAB SinФ, where B = Magnetic field, Ф = Angle
Then,
T = Magnetic dipole moment*B*SinФ = 0.184*12*Sin 41 = 1.447 Nm
Answer:
2.74
Explanation:
Magnification = image distance/object distance
Mag = v/u
Given
v = 46cm
u = 16.8
Magnification = 46/16.8
Magnification = 2.74
Hence the magnification is 2.74
To solve this problem it is necessary to apply the concepts related to wavelength depending on the frequency and speed. Mathematically, the wavelength can be expressed as
Where,
v = Velocity
f = Frequency,
Our values are given as
L = 3.6m
v= 192m/s
f= 320Hz
Replacing we have that
The total number of 'wavelengths' that will be in the string will be subject to the total length over the size of each of these undulations, that is,
Therefore the number of wavelengths of the wave fit on the string is 6.