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kati45 [8]
3 years ago
14

The oxidation numbers of nitrogen in nh3, hno3, and no2 are, respectively:

Chemistry
2 answers:
vovikov84 [41]3 years ago
3 0
The oxidation numbers for Nitrogen are respectively -3, +5, +4
julia-pushkina [17]3 years ago
3 0

Answer:

The oxidation number are

NH₃: -3

HNO₃ : +5

NO₂ : +4

Explanation:

The oxidation number is calculated considering that

a) oxidation number of hydrogen is +1 in all compounds except hydrides

b) oxidation number of oxygen is -2 in all compound except peroxides, superoxides and compound of fluorine.

a) NH₃ : let the oxidation number of nitrogen is "x"

x + 3 (+1) = 0

Therefore x = -3

b) HNO₃

Let the oxidation number of nitrogen is "x"

+1 + x +3(-2) = 0

x = -5.

c) NO₂

Let oxidation number of nitrogen ix "x"

x + 2(-2)= 0

x = +4

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What does the host mean when he says that the acid has "donated a proton" to the water?
weqwewe [10]

Answer:

Option B

Explanation:

As Brønsted-Lowry theory states, acids are the ones that can donate protons.

When a proton is donated, it is released to become medium more acidic.

HCl is a strong acid.

HCl (l) + H₂O (l)  →  H₃O⁺ (aq) +  Cl⁻(aq)

These always reffers to strong acid where the dissociation is 100% completed.

In a weak acid, dissociation is not 100% complete, that's why we have an equilibrium.

HA (l) + H₂O (l)  ⇄  H₃O⁺ (aq) +  A⁻(aq)                   Ka

5 0
2 years ago
A particle that has a negative charge Electrons Protons Non-polarMolecule Neutrons
murzikaleks [220]
Electron 

 ~~~hope this helps~~~
~~have a beautiful day~~
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7 0
3 years ago
How many moles of nitrogen trifluoride (NF3) can be produced from 9.65 mole of Fluorine gas (F2)
user100 [1]

Answer:

6.43 moles of NF₃.

Explanation:

The balanced equation for the reaction is given below:

N₂ + 3F₂ —> 2NF₃

From the balanced equation above,

3 moles of F₂ reacted to produce 2 moles of NF₃.

Finally, we shall determine the number of mole of nitrogen trifluoride (NF₃) produced by the reaction of 9.65 moles of Fluorine gas (F₂). This can be obtained as follow:

From the balanced equation above,

3 moles of F₂ reacted to produce 2 moles of NF₃.

Therefore, 9.65 moles of F₂ will react to to produce = (9.65 × 2)/3 = 6.43 moles of NF₃.

Thus, 6.43 moles of NF₃ were obtained from the reaction.

4 0
3 years ago
How many milliliters of water are needed to prepare a 3.5M solution of NaOH if you have .5mol of the solute
Mamont248 [21]

Answer:

1335.12 mL of H2O

Explanation:

To calculate the mililiters of water that the solution needs, it is necessary to know that the volume of the solution is equal to the volume of the solute (NaOH) plus the volume of the solvent (H2O).

From the molarity formula we can first calculate the volume of the solution:

M=\frac{solute moles}{solution volume}

Solutionvolume=\frac{solute moles}{M} =\frac{5mol}{3.5\frac{mol}{L} } =1.429L

The volume of the solution as we said previously is:

Solution volume = solute volume + solvent volume

To determine the volume of the solute we first obtain the grams of NaOH through the molecular weight formula:

MW=\frac{mass}{mol}

Mass=MW*mol=39.997\frac{g}{mol} *5mol=199.985g

Now with the density of NaOH the milliliters of solute can be determined:

d=\frac{mass}{volume}

Volume=\frac{mass}{d} =\frac{199.985g}{2.13\frac{g}{mL} } =93.88mL of NaOH

Having the volume of the solution and the volume of the solute, the volume of the solvent H2O can be calculated:

Solvent volume = solution volume - solute volume

Solvent volume = 1429 mL -  93.88 mL = 1335.12 mL of H2O

7 0
3 years ago
How to convert 151cm to km
maw [93]
Just multiply 151 x 0.0001

That will equal:

0.00151 km or if you want to round it then it would be 0.02km
5 0
3 years ago
Read 2 more answers
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